Answer:
The temperature change from the combustion of the glucose is 6.097°C.
Explanation:
Benzoic acid;
Enthaply of combustion of benzoic acid = 3,228 kJ/mol
Mass of benzoic acid = 0.570 g
Moles of benzoic acid = 
Energy released by 0.004667 moles of benzoic acid on combustion:
Heat capacity of the calorimeter = C
Change in temperature of the calorimeter = ΔT = 2.053°C
Glucose:
Enthaply of combustion of glucose= 2,780 kJ/mol.
Mass of glucose=2.900 g
Moles of glucose = 
Energy released by the 0.016097 moles of calorimeter combustion:
Heat capacity of the calorimeter = C (calculated above)
Change in temperature of the calorimeter on combustion of glucose = ΔT'
The temperature change from the combustion of the glucose is 6.097°C.
Answer:
amount of silver chloride required is 0.015 moles or 2.1504 g
Explanation:
0.1M AgCL means 0.1mol/dm³ or 0.1mol/L
1L = 1000mL
if 0.1mol of AgCl is contained in 1000mL of solution
then x will be contained in 150mL of solution
cross multiply to find x
x = (0.1*150)/1000
x= 0.015 moles
moles of silver chloride present in 150 mL of solution is 0.15 moles
To convert this to grams, simply multiply this value by the molar mass of silver chloride
molar mass of silver chloride AgCl =107.86 + 35.5
=143.36 g/mol
mass of AgCl = moles *molar mass
=0.015*143.36
=2.1504g
=
Answer:
The volume for the ideal gas is: 4647.5 Liters
Explanation:
Formula for the Ideal Gases Law must be applied to solve this question:
P . V = n . R . T
We convert the T° to K → 100°C + 273 = 373 K
We convert pressure value from kPa to atm.
2 kPa . 1atm/101.3 kPa = 0.0197 atm
We replace data in the formula.
V = ( n . R . T) / P → (3 mol . 0.082 . 373K) / 0.0197 atm =
The volume for the ideal gas is: 4647.5 Liters
When the balanced reaction equation is:
2HCl(aq) + Ca(OH)2(aq) → CaCl2(aq) + 2H2O(l)
from the balanced equation, we can get the molar ratio between HCl & Ca(OH)2
2:1
∴ the volume of Ca(OH)2 = 15.8 L HCl * 1.51 m HCl * (1mol Ca(OH)2/ 2mol HCl) * (1L ca(OH)2/0.585 mol Ca(OH)2
= 20.4 L
