Answer: C.) John Herschel
Answer:
A) Upper bound modulus of elasticity; E = 165.6 GPa
B) Lower bound modulus of elasticity; E = 83.09 GPa
Explanation:
A) Formula for upper bound modulus is given as;
E = E_m(1 - V_f) + E_f•V_f
We are given;
E_m = 60 GPa
E_f = 380 GPa
V_f = 33% = 0.33
Thus,
E = 60(1 - 0.33) + 380(0.33)
E = (60 x 0.67) + 125.4
E = 165.6 GPa
B) Formula for lower bound modulus is given as;
E = 1/[(V_f/E_f) + ((1 – V_f)/E_m)]
E = 1/[(0.33/380) + ((1 – 0.33)/60)]
E = 1/(0.0008684 + 0.01116667)
E = 1/0.01203507
E = 83.09 GPa
Answer:
a) 19 or select the closest answer
b) 5%
Explanation:
a)
from the voltage divide rule
Select the nearest answer
b)
obtained gain = 
Expected gain = 
∴ error = |
| × 100
= 1/20 × 100
= 5%
Answer:
A)
- Q ( kw ) for vapor = -1258.05 kw
- Q ( kw ) for liquid = -1146.3 kw
B )
- Q ( kj ) for vapor = -1258.05 kJ
- Q ( KJ ) for liquid = - 1146.3 KJ
Explanation:
Given data :
45.00 % mole of methane
55.00 % of ethane
attached below is a detailed solution
A) calculate - Q(kw)
- Q ( kw ) for vapor = -1258.05 kw
- Q ( kw ) for liquid = -1146.3 kw
B ) calculate - Q ( KJ )
- Q ( kj ) for vapor = -1258.05 kJ
- Q ( KJ ) for liquid = - 1146.3 KJ
since combustion takes place in a constant-volume batch reactor
Answer:
Option (C)
Explanation:
A tool is usually defined as an equipment or a device that is hold by the hands and is used to carry out a particular function. For example, a hammer is a tool that is used to hit on a hard surface.
A tool can be considered as a technology under a certain condition, such as the applications of this objects are helpful in solving a practical problem, with ease and comfortability.
Thus, the correct answer is option (C).
