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maria [59]
3 years ago
14

t the R group in the reagent over the arrow be isopropyl. (i.e. The reagent is LiN[CH(CH3)2]2.) Now, fill in the blanks. This re

action will follow ______ rule and will form the _________ substituted alkene. a. Zaitzev's; more b. Zaitzev's; less c. Hofmann's; less d. Hofmann's; more
Chemistry
2 answers:
vladimir2022 [97]3 years ago
6 0

Answer:. A

Explanation:

T the R group in the reagent over the arrow be isopropyl. (i.e. The reagent is LiN[CH(CH3)2]2.) Now, fill in the blanks. This reaction will follow Zaitzev'srule and will form the more substituted alkene.

Tanzania [10]3 years ago
3 0

Answer:c. Hofmann's; less

Explanation:

The Hofmann elimination process, named after its discoverer, the German chemist August Wilhelm Von Hofmann rule states that the major alkene product is the <u>least substituted </u>and least stable product when it comes to asymmetrical amines.  The Hofmann elimination can be illustrated in t e formation of “Hoffman” products in elimination reactions  using a less common, LDA LiN[CH(CH3)2]2  Lithium Di-isopropyl Amide (LDA) usually with base  potassium t-butoxide  which will give rise to a less substituted alkene.

This reaction will follow Hofmann's_____ rule and will form the ___less______ substituted alkene.

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Select all that apply. Catalysts can save money by essentially lowering the:
k0ka [10]

Answer: Options (a) and (d) are the correct answer.

Explanation:

A catalyst is the substance which helps in increasing the rate of reaction.

Activation energy is the minimum amount of energy required by reactants to start the reaction. On addition of catalyst, the path of reaction changes because the energy barrier gap reduces and hence, the activation energy also decreases.

In the absence of catalyst, we need to increase the temperature so that reaction can occur quickly.

Whereas on addition of catalyst, there is no need to increase the temperature as the catalyst itself is sufficient to increase the rate of reaction. As a result, temperature should be lowered when there is addition of catalyst in the reaction.

Thus, we can conclude that catalysts can save money by essentially lowering the activation energy and temperature required.


4 0
3 years ago
Read 2 more answers
To titrate 45.00 milliliters of an unknown HCl sample, use 25.00 milliliters of a standard 0.2000 M NaOH titrant. What is the mo
gtnhenbr [62]
V ( HCl ) = 45.00 mL in liters : 45.00 / 1000 => 0.045 L

M ( HCl ) = ?

V ( NaOH ) = 25.00 / 1000 => 0.025 L 

M ( NaOH) = 0.2000 M

number of moles NaOH :

n = M x V = 0.2000 x 0.025 => 0.005 moles of NaOH

Mole ratio:

HCl + NaOH = NaCl + H2O

1 mole HCl ---------- 1 mole NaOH
? mole HCl ---------- 0.005 moles NaOH

moles HCl = 0.005 x 1 / 1

= 0.005 moles of HCl :

M ( HCl ) = n / V

M ( HCl ) = 0.005 / 0.045

= 0.1111 M

hope this helps!




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