1: B
2: B
3: A
4: A
5: D
Hope this helps!
Answer:
Sodium oxide reacts exothermically with cold water to produce sodium hydroxide solution. A concentrated solution of sodium oxide in water will have pH 14. ... For example, it reacts with dilute hydrochloric acid to produce sodium chloride solution.
<u>Answer:</u> The concentration of radon after the given time is ![3.83\times 10^{-30}mol/L](https://tex.z-dn.net/?f=3.83%5Ctimes%2010%5E%7B-30%7Dmol%2FL)
<u>Explanation:</u>
All the radioactive reactions follows first order kinetics.
The equation used to calculate half life for first order kinetics:
![t_{1/2}=\frac{0.693}{k}](https://tex.z-dn.net/?f=t_%7B1%2F2%7D%3D%5Cfrac%7B0.693%7D%7Bk%7D)
We are given:
![t_{1/2}=3.82days](https://tex.z-dn.net/?f=t_%7B1%2F2%7D%3D3.82days)
Putting values in above equation, we get:
![k=\frac{0.693}{3.82}=0.181days^{-1}](https://tex.z-dn.net/?f=k%3D%5Cfrac%7B0.693%7D%7B3.82%7D%3D0.181days%5E%7B-1%7D)
Rate law expression for first order kinetics is given by the equation:
![k=\frac{2.303}{t}\log\frac{[A_o]}{[A]}](https://tex.z-dn.net/?f=k%3D%5Cfrac%7B2.303%7D%7Bt%7D%5Clog%5Cfrac%7B%5BA_o%5D%7D%7B%5BA%5D%7D)
where,
k = rate constant = ![0.181days^{-1}](https://tex.z-dn.net/?f=0.181days%5E%7B-1%7D)
t = time taken for decay process = 3.00 days
= initial amount of the reactant = ![1.45\times 10^{-6}mol/L](https://tex.z-dn.net/?f=1.45%5Ctimes%2010%5E%7B-6%7Dmol%2FL)
[A] = amount left after decay process = ?
Putting values in above equation, we get:
![0.181days^{-1}=\frac{2.303}{3.00days}\log\frac{1.45\times 10^{-6}}{[A]}](https://tex.z-dn.net/?f=0.181days%5E%7B-1%7D%3D%5Cfrac%7B2.303%7D%7B3.00days%7D%5Clog%5Cfrac%7B1.45%5Ctimes%2010%5E%7B-6%7D%7D%7B%5BA%5D%7D)
![[A]=3.83\times 10^{-30}mol/L](https://tex.z-dn.net/?f=%5BA%5D%3D3.83%5Ctimes%2010%5E%7B-30%7Dmol%2FL)
Hence, the concentration of radon after the given time is ![3.83\times 10^{-30}mol/L](https://tex.z-dn.net/?f=3.83%5Ctimes%2010%5E%7B-30%7Dmol%2FL)
Answer:
There is no single variable that never changes in the combined gas law