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3 years ago

When one atom contributes both bonding electrons in a single covalent bond, the bond is called a(n) ____?

Chemistry

2 answers:

andre [41]3 years ago

7 0

Coordinate covalent bond

Damm [24]3 years ago

7 0

Answer:

coordinate covalent bond

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For the following reaction, 22.9 grams of nitrogen monoxide are allowed to react with 5.80 grams of hydrogen gas. nitrogen monox

ololo11 [35]

Answer:

1) Maximun ammount of nitrogen gas: $m_{N2}=10.682 g N_2$

2) Limiting reagent: $NO$

3) Ammount of excess reagent: $m_{N2}=4.274 g$

Explanation:

The reaction

$2 NO (g) + 2 H_2 (g) \longrightarrow N_2 (g) + 2 H_2O (g)$

Moles of nitrogen monoxide

Molecular weight: $M_{NO}=30 g/mol$

$n_{NO}=\frac{m_{NO}}{M_{NO}}$

$n_{NO}=\frac{22.9 g}{30 g/mol}=0.763 mol$

Moles of hydrogen

Molecular weight: $M_{H2}=2 g/mol$

$n_{H2}=\frac{m_{H2}}{M_{H2}}$

$n_{H2}=\frac{.5.8 g}{2 g/mol}=2.9 mol$

Mol rate of H2 and NO is 1:1 => hydrogen gas is in excess

1) Maximun ammount of nitrogen gas => when all NO reacted

$m_{N2}=0.763 mol NO* \frac{1 mol N_2}{2 mol NO}*\frac{28 g N_2}{mol N_2}$

$m_{N2}=10.682 g N_2$

2) Limiting reagent: $NO$

3) Ammount of excess reagent:

$m_{N2}=(2.9 mol - 0.763 mol NO* \frac{1 mol H_2}{1 mol NO})*\frac{2 g H_2}{mol H_2}$

$m_{N2}=4.274 g$

8 0

3 years ago

What is responsible for the blue sky?

andreev551 [17]

Answer:

well for me it's

Explanation:

The reflection of the seas

7 0

2 years ago

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Given the following equation: 2K + Cl2 -> 2KCl How many grams of KCl is produced from 4.00 g of K and excess Cl2?

Thepotemich [5.8K]

Answer:

42.65g

Explanation:

Given parameters:

Mass of K = 4g

Unknown: Mass of KCl

Solution:

Complete equation of the reaction:

2K + Cl₂ → 2KCl

To solve this problem, we know that the reactant in short supply is potassium K and this dictates the amount of products that would be formed. The chlorine gas is in excess and we can't use it to determine the amount of product that would form.

Now, we work from the known to the unknown. Since we know the mass of K given in the reaction, we can simply find the molar relationship between the reacting potassium and the product. We simply convert the mass to mole and compare to the product. From there we can find the mass of KCl that would be produced.

Calculating number of moles of K

Number of moles = $\frac{mass}{molar mass}$

Number of moles of K = $\frac{4}{39}$ = 0.103mol

From the given reaction equation:

2 moles of K will produce 2 moles of KCl

Therefore 0.103mol of K will produce 0.103mol of KCl

To find the mass of KCl produced,

Mass of KCl = number of moles of KCl x molar mass

Molar mass of KCl = 39 + 35.5 = 74.5gmol⁻¹

Mass of KCl = 0.103 x 74.5 = 42.65g

4 0

2 years ago

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What will lithium and bromine make when they bond

Rus_ich [418]

Answer:

they will form a compound

5 0

2 years ago

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Sometimes you are given a measured amount of two or more reactants and asked how much product can be formed. Explain what steps

Westkost [7]

Explanation:

To solve this problem, follow these steps;

Obtain a balanced equation of the reaction and familiarize with the reactants and products.
Find the number of moles of the reacting species since they are the known matter in terms of quantity.
From the number of moles, determine the limiting reactant.
The limiting reactant is the one given in short supply.
Such reactant determines the extent of the reaction.
Compare the moles of this specie to that of the products using the balanced equation.
Obtain the mole of the desired product and find the mass or desired quantity.
simply work from the known specie to the unknown

learn more:

Number of moles brainly.com/question/13064292

#learnwithBrainly

4 0

3 years ago