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Answer:
2.16 MeV
Explanation:
To determine the amount of work done that is needed to assemble the atomic mass; we need to apply the equation;
U =
where:
= proportionality constant =
e = magnitude of the charge of each electron =
r = length of each side of the vertex =
So; replacing our values into above equation; we have:
U =
U = 3.456 × 10 ⁻¹³ J
If we have to convert our unit from J to Mev; then we are going to have:
U = 3.456 × 10 ⁻¹³ J
U = 2.16 MeV
Therefore, the amount of work done needed to assemble an atomic nucleus = 2.16 MeV
The reactants of the reaction will be solid gold (III) sulfide and hydrogen gas, while the products will be pure solid gold and hydrogen sulfide gas.
<h3>Chemical reactions</h3>Reactants react together during reactions to arrive at products.
In this case, solid gold (III) sulfide and hydrogen gas react according to the following equation:
Reactants = solid gold (III) sulfide, hydrogen gas
Products: pure solid gold, hydrogen sulfide gas
More on chemical reactions can be found here: brainly.com/question/1689737