Answer:
894 deg K
Explanation:
The computation is shown below:
Given that
V1 denotes the initial volume of gas = 2.00 L
T1 denotes the initial temperature of gas = 25 + 273 = 298 K
V2 denotes the final volume of gas = 6.00 L
T2 = ?
Based on the above information
Here we assume that the pressure is remain constant,
So,
V1 ÷ T1 = V2 ÷ T2
T2 = T1 × V2 ÷ V1
= (298)(6) ÷ (2)
= 894 deg K
The amount of heat needed to melt 423 g of water at 0°C is 141282 J
The heat required to melt water can be obtained by using the following formula:
<h3>Q = mL </h3>
Q is the heat required.
L is the latent heat of fusion (334 J/g)
m is the mass.
With the above formula, we can obtain the heat required to melt the water as illustrated below:
Mass of water (m) = 423 g
Latent heat of fusion (L) = 334 J/g
<h3>Heat (Q) required =? </h3>
Q = mL
Q = 423 × 334
<h3>Q = 141282 J</h3>
Therefore, the amount of heat needed to melt 423 g of water at 0°C is 141282 J
Learn more: brainly.com/question/17084080
Nitrogen fixation means form nitrits and dentrification means nitrits will not formed
1 answer · Chemistry
Best Answer
Water steam condenses if its pressure is equal to vapor saturation vapor pressure.
Use the Clausius-Clapeyron relation.
I states the temperature gradient of the saturation pressure is equal to the quotient of molar enthalpy of phase change divided by molar volume change due to phase transition time temperature:
dp/dT = ΔH / (T·ΔV)
Because liquid volume is small compared to vapor volume
ΔV in vaporization is approximately equal to to the vapor volume. Further assume ideal gas phase:
ΔV ≈ V_v = R·T/p
Hence
dp/dT = ΔHv / (R·T²/p)
<=>
dlnp/dT = ΔHv / (R·T²)
If you solve this DE an apply boundary condition p(T₀)= p₀.
you get the common form:
ln(p/p₀) = (ΔHv/R)·(1/T₀ - 1/T)
<=>
p = p₀·exp{(ΔHv/R)·(1/T₀ - 1/T)}
For this problem use normal boiling point of water as reference point:
T₀ =100°C = 373.15K and p₀ = 1atm
Therefore the saturation vapor pressure at
T = 350°C = 623.15K
is
p = 1atm ·exp{(40700J / 8.314472kJ/mol)·(1/373.15K - 1/623.15K)} = 193 atm
hope this helps
Answer:
2H₂ + O₂ → 2H₂O.
Explanation:
- For the reaction of water formation:
<em>2H₂ + O₂ → 2H₂O.</em>
- It should apply the the law of conservation of mass that the no. of reactants atoms is equal to the no. of products atoms.
<em>So, every </em><em>2.0 moles of H₂ </em><em>react with </em><em>1.0 mole of O₂</em><em> to produce </em><em>2.0 moles of H₂O.</em>
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