Answer:
snow is 64.638 kg / hr
Explanation:
Given data
wide w = 21 feet
long L = 20 ft
area A = 1350 square foot
mass of snow m = 1.90 mg
to find out
snow in kilograms / hour
solution
we will find snow in kg
so we apply formula that is
snow kg / hour = w × L ×A × m × 60/10^6
put all value we get snow
snow = 21 × 20 × 1350 × 1.90 × 60/10^6
snow = 420 × 1350 × 1.90 × 60/10^6
snow = 1077300 × 60/10^6
snow = 64.638
hence snow is 64.638 kg / hr
Answer:
7. I and III only.
Explanation:
Only portions of the electromagnetic spectrum is visible to the human eye. Electromagnetic radiation in this range of wavelengths is called visible light which have wavelengths from about 390 to 750 nm that is; ultraviolet light and visible light.
Explanation:
It is given that,
Total weight of the piston, W = F = 70 N
Area of the piston, 
Let P is the pressure exerted on the piston by the gas. The force per unit area is called the pressure exerted pressure of the gas. Mathematically, it is given by :



We know that the atmospheric pressure is given by :

So, the pressure is given by :



Hence, this is the required solution.
Complete Question:
Metal sphere A has a charge of − Q . −Q. An identical metal sphere B has a charge of + 2 Q . +2Q. The magnitude of the electric force on sphere B due to sphere A is F . F. The magnitude of the electric force on sphere A due to sphere B must be:
A. 2F
B. F/4
C. F/2
D. F
E. 4F
Answer:
D.
Explanation:
If both spheres can be treated as point charges, they must obey the Coulomb's law, that can be written as follows (in magnitude):

As it can be seen, this force is proportional to the product of the charges, so it must be the same for both charges.
As this force obeys also the Newton's 3rd Law, we conclude that the magnitude of the electric force on sphere A due to sphere B, must be equal to the the magnitude of the force on the sphere B due to the sphere A, i.e., just F.