Answer:
E) True. The girl has a larger tangential acceleration than the boy.
Explanation:
In this exercise they do not ask us to say which statement is correct, for this we propose the solution to the problem.
Angular and linear quantities are related
v = w r
a = α r
the boy's radius is r₁ = 1.2m the girl's radius is r₂ = 1.8m
as the merry-go-round rotates at a constant angular velocity this is the same for both, but the tangential velocity is different
v₁ = w 1,2 (boy)
v₂ = w 1.8 (girl)
whereby
v₂> v₁
reviewing the claims we have
a₁ = α 1,2
a₂ = α 1.8
a₂> a₁
A) False. Tangential velocity is different from zero
B) False angular acceleration is the same for both
C) False. It is the opposite, according to the previous analysis
D) False. Angular acceleration is equal
E) True. You agree with the analysis above,
Answer:17.08 s
Explanation:
Given
distance between First and second Runner is 45.6 m
speed of first runner
=3.1 m/s
speed of second runner
=4.65 m/s
Distance between first runner and finish line is 250 m
Second runner need to run a distance of 250+45.6=295.6 m
Time required by second runner 
time required by first runner to reach finish line
Thus second runner reach the finish line 80.64-63.56=17.08 s earlier
overuse of a muscle Answer:
Explanation:
Answer:
Chemical bonds
Explanation:
The chemical bonds hold the different type atoms or ions together.
The type of chemical bonds :
1. Ionic bond ;
Ions or atoms changes the electron and form ionic bond.Those atoms gains the electron gets negative charge and those atoms donate the electron gets positive charge.
2.Covalent bond :
In this type of bond atoms share the electrons and form covalent bonds.
3. Metallic bond :
This type of bond are present in the metals.In this atoms are used free electrons to form bonds.
Therefore answer is --
Chemical bonds
Given that
Work = 600,000 J ,
distance(S) = 500 m ,
mass (m) = 250 Kg ,
Determine the velocity of car (v) = ?
We know that,
Work = Force × distance
=> Force = Work ÷ distance
= 600,000 ÷ 500
= 500 N .
Also Force F = m.a ; from Newtons II law
500 = 250 × a
a = 2 m/s.
<em>Final Velocity from the given formula </em>
V² = u² + 2.a.s
= 0 + 2 × 2 × 500
= \sqrt{2000}
<em> v = 44.7 m/s</em>
