Answer: A maximum of 1 hour
Explanation:
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Answer:
Water enters a centrifugal pump axially at atmospheric pressure at a rate of 0.12 m3/s and at a velocity of 7 m/s, and leaves in the normal direction along the pump casing, as shown in Fig. PI3-39. Determine the force acting on the shaft (which is also the force acting on the bearing of the shaft) in the axial direction.
Step-by-step solution:
Step 1 of 5
Given data:-
The velocity of water is .
The water flow rate is.
extension lines,sketches,leader lines,dimensions describes all illustrations created by freehand.
Answer:
Time period = 41654.08 s
Explanation:
Given data:
Internal volume is 210 m^3
Rate of air infiltration ![9.4 \times 10^{-5} kg/s](https://tex.z-dn.net/?f=9.4%20%5Ctimes%2010%5E%7B-5%7D%20kg%2Fs)
length of cracks 62 m
air density = 1.186 kg/m^3
Total rate of air infiltration ![= 9.4\times 10^{-5} \times 62 = 582.8\times 10{-5} kg/s](https://tex.z-dn.net/?f=%3D%209.4%5Ctimes%2010%5E%7B-5%7D%20%5Ctimes%2062%20%3D%20582.8%5Ctimes%2010%7B-5%7D%20kg%2Fs)
total volume of air infiltration![= \frac{582.8\times 10{-5}}{1.156} = 5.04\times 10^{-3} m^3/s](https://tex.z-dn.net/?f=%20%3D%20%5Cfrac%7B582.8%5Ctimes%2010%7B-5%7D%7D%7B1.156%7D%20%3D%205.04%5Ctimes%2010%5E%7B-3%7D%20m%5E3%2Fs)
Time period ![= \frac{210}{5.04\times 10^{-3}} = 41654.08 s](https://tex.z-dn.net/?f=%3D%20%5Cfrac%7B210%7D%7B5.04%5Ctimes%2010%5E%7B-3%7D%7D%20%3D%2041654.08%20s)