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3 years ago

1000-kg car travelling down on a steepest road, which has inclined angle of 18

Physics

1 answer:

eduard3 years ago

8 0

Answer:

Explanation:

it was thinking about how much and then the other than you can get it would be able to ask her to be able and then the way you have been sent from your browser

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What are the importance of wedge? <br>

FromTheMoon [43]

A wedge is a machine and it is used for separating bodies.

<h3 /><h3>The Wedge as a Machine</h3>

The wedge is a combination of two inclined planes. When the wedge is driven into a body by an effort force, a much larger force will be exerted to each side by the wedge surfaces.

What are the importance of wedge?

A wedge is used to separate bodies which are held together by large forces example of this scenario is splitting of timber. A wedge is a machine and the example of wedge - type of machine are;

Axes

Chisel

Knives

Cutting tools

Note that a thin wedge has a higher mechanical advantage than a short thick one.

Therefore, a wedge is a machine and it is used for separating bodies.

Learn more about machine here: brainly.com/question/2337612

#SPJ1

3 0

2 years ago

If sounds actually moves like a longitudinal wave, then why did our oscilloscoop on our phone pick up sound waves as a transvers

SIZIF [17.4K]

Sound from vibrating body produces longitudinal wave in air

Mark as brainlest please

5 0

3 years ago

A point charge q = +4.50 nC moves through a potential difference ΔV = Vf − Vi = +27.0 V. What is the change in the electric pote

olganol [36]

Change in electric potential energy: 121.5 nJ

Explanation:

For a charged particle moving in an electric field, the change in electric potential energy of the particle is given by

$\Delta U = q \Delta V$

where:

q is the charge of the particle

$\Delta V$ is the potential difference between the initial and final position of the particle

For the point charge in this problem, we have:

$q=+4.50 nC$ is the charge

$\Delta V=+27.0 V$ is the potential difference

Therefore, the change in electric potential energy is

$\Delta U=(+4.50)(+27.0)=121.5 nJ$

Learn more about electric fields:

brainly.com/question/8960054

brainly.com/question/4273177

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6 0

3 years ago

The battery for a certain cell phone is rated at 3.70 V. According to the manufacturer it can produce math]3.15 \times 10^{4} J[

AysviL [449]

Answer:

The average current that this cell phone draws when turned on is 0.451 A.

Explanation:

Given;

voltage of the phone, V = 3.7 V

electrical energy of the phone battery, E = 3.15 x 10⁴ J

duration of battery energy, t = 5.25 h

The power the cell phone draws when turned on, is the rate of energy consumption, and this is calculated as follows;

$P = \frac{E}{t}$

where;

P is power in watts

E is energy in Joules

t is time in seconds

$P = \frac{3.15*10^4}{5.25*3600s} = 1.667 \ W$

The average current that this cell phone draws when turned on:

P = IV

$I = \frac{P}{V} =\frac{1.667}{3.7} = 0.451 \ A$

Therefore, the average current that this cell phone draws when turned on is 0.451 A.

5 0

3 years ago

What is the gravitational acceleration close to the surface of a planet with a mass of 9ME and radius of 3RE, where ME and RE ar

Papessa [141]

Answer:

9.78 m/s²

Explanation:

To solve this, we use the gravitational formula

g = GM/r², where

g = acceleration due to gravity

G = gravitational constant

M = mass of the planet

r = radius of the planet

From the question, we got that the mass of the planet is

M = 9ME, where ME = 5.95*10^24

M = 9 * 5.95*10^24

M = 5.355*10^25 kg

Also, the Radius of the planet, R = 3RE, where RE = 6.37*10^6

R = 3 * 6.37*10^6

R = 1.911*10^7 m

On applying the values of both R and M to the equation, we get

g = GM/r²

g = (6.67*10^-11 * 5.355*10^25) / (1.911*10^7)²

g = 3.57*10^15/3.65*10^14

g = 9.78 m/s²

Therefore, the acceleration due to gravity on the planet is 9.78 m/s²

Please vote brainliest if it helped you <3

5 0

3 years ago