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Dima020 [189]
3 years ago
15

An object moves in a circle with a period of 0.025 hours. What is its frequency in Hz?

Physics
1 answer:
Sedaia [141]3 years ago
7 0

Answer:

40 Hz

Explanation:

f = 1/T = 1 / 0.025 = 40 Hz

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A box is being pushed from the left with a force of 5 N. No force is being applied from the right.
Sergio039 [100]

Answer:

The box will move to the right with increasing speed

Explanation:

According to Newton's second law:

F=ma (1)

where

F is the net force on an object

m is the mass of the object

a is its acceleration

For the box in this problem, there is only one force acting on it: a force of 5 N from the left (so, to the right). This means that according to (1) the box will experience an acceleration: the direction of the acceleration is the same as the direction of the net force (so, to the right), therefore the box will move to the right and its speed will continue increasing due to fact that it is being accelerated.

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At which life cycle stage are stars most stable
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~Hello there!

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Please help me! <br>to prove this equation of a thin convex lens..​
kipiarov [429]

Answer:

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3 years ago
A cyclist reduces his speed from 6.5 m/s to 0.0 m/s with an acceleration of
kolbaska11 [484]

Answer:

a= -1.2 m/s^2

Vi= 6.5 m/s

Vf= 0 m/s

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Explanation:

4 0
3 years ago
)If a force of 5.00 N is needed to open a 90.0 cm wide door when applied at the edge opposite the hinges, what force must be app
masha68 [24]

Answer:

A force of 12.857 newtons must be applied to open the door.

Explanation:

In this case, a force is exerted on the door, a moment is performed and the door is opened. If moment remains constant, the force is inversely proportional to distance respect to axis of rotation passing through hinges. That is:

F \propto \frac{1}{r}

F = \frac{k}{r} (Eq. 1)

Where:

F - Force, measured in newtons.

k - Proportionality ratio, measured in newton-meters.

r - Distance respect to axis of rotation passing through hinges, measured in meters.

From (Eq. 1) we get the following relationship and clear the final force within:

F_{A}\cdot r_{A} = F_{B}\cdot r_{B}

F_{B}=\left(\frac{r_{A}}{r_{B}} \right)\cdot F_{A}(Eq. 2)

Where:

F_{A}, F_{B} - Initial and final forces, measured in newtons.

r_{A}, r_{B} - Initial and final distances, measured in meters.

If we know that F_{A} = 5\,N, r_{A} = 0.9\,m and r_{B} = 0.35\,m, then final force is:

F_{B}= \left(\frac{0.9\,m}{0.35\,m} \right)\cdot (5\,N)

F_{B} = 12.857\,N

A force of 12.857 newtons must be applied to open the door.

3 0
3 years ago
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