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Dima020 [189]
2 years ago
15

An object moves in a circle with a period of 0.025 hours. What is its frequency in Hz?

Physics
1 answer:
Sedaia [141]2 years ago
7 0

Answer:

40 Hz

Explanation:

f = 1/T = 1 / 0.025 = 40 Hz

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The downlink frequency is lower than the uplink frequency. True or False
miv72 [106K]

Answer:

I think it is true

Explanation:

4 0
3 years ago
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These the flow of electrons (the current) and where some of the electrons' energy gets converted into heat. (Lessons 5.01-5.03)
liq [111]

Answer:

Conductors.

Explanation:

Conductors allow the flow of electrons i. e. the current and where some of the electrons energy gets converted into heat while some electrons energy converted into light. Conductors are the materials which has the ability to allow heat and electricity to flow through them. Metals such as gold, copper, Silver, Aluminum, Mercury, Steel, Iron and salty water etc are good conductors of heat and electricity.

3 0
3 years ago
A jet liner must reach a speed of 82 m/s for takeoff. If the
SIZIF [17.4K]

Answer:

The acceleration that the jet liner that must have is 2.241 meters per square second.

Explanation:

Let suppose that the jet liner accelerates uniformly. From statement we know the initial (v_{o}) and final speeds (v_{f}), measured in meters per second, of the aircraft and likewise the runway length (d), measured in meters. The following kinematic equation is used to calculate the minimum acceleration needed (a), measured in meters per square second:

a = \frac{v_{f}^{2}-v_{o}^{2}}{2\cdot d}

If we know that v_{o} = 0\,\frac{m}{s}, v_{f} = 82\,\frac{m}{s} and d = 1500\,m, then the acceleration that the jet must have is:

a = \frac{\left(82\,\frac{m}{s} \right)^{2}-\left(0\,\frac{m}{s} \right)^{2}}{2\cdot (1500\,m)}

a = 2.241\,\frac{m}{s^{2}}

The acceleration that the jet liner that must have is 2.241 meters per square second.

3 0
2 years ago
1. If I dig a 6FT hole how deep is that hole?
iren [92.7K]

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For the first one its about 25 feet

Explanation:

5 0
3 years ago
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In a simple electric circuit, a 110-volt electric heater
Readme [11.4K]

Answer: 55 ohms

Explanation:

Given that,

Voltage of heater (v) = 110-volt

Current drawn by heater (I) = 2.0 amperes

resistance of the heater (r) = ?

Since voltage, current and resistance are involved, apply the formula for ohms law.

Voltage = current x resistance

i.e v = ir

where r = v / i

r = 110 volts / 2.0 A

r = 55 ohms

Thus, the resistance of the heater is 55 ohms

6 0
3 years ago
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