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Ronch [10]
2 years ago
7

A warehouse contains 55 boxes. Then a truck delivers a number of boxes at 12:00 p.m. and the team begins to unload them immediat

ely. By 3:00 p.m., the ware house contains 90 boxes. Suppose the boxes are unloaded at a constant rate. How many boxes are in the warehouse when the truck is finally empty at 8:30 p.m.?
GIVE BRAINLIEST TO CORRECT ANSWER ONLY
Mathematics
2 answers:
ollegr [7]2 years ago
7 0

Answer:

154 boxes

Step-by-step explanation:

Phantasy [73]2 years ago
6 0

Answer:

154 boxes

mark me the brainliest

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Suppose that a standardized biology exam has a mean score of 80% correct, with a standard deviation of 3. The school administrat
NemiM [27]

Answer:

The 99% confidence interval is between 62.36%(lower bound) and 89.64%(upper bound).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

A sample of 65 students from the freshmen class is used and a mean score of 76% correct is obtained.

This means that n = 65, \pi = 0.76

99% confidence level

So \alpha = 0.005, z is the value of Z that has a pvalue of 1 - \frac{0.005}{2} = 0.995, so Z = 2.575.

The lower limit of this interval is:

\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.76 - 2.575\sqrt{\frac{0.76*0.24}{65}} = 0.6236

The upper limit of this interval is:

\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.76 + 2.575\sqrt{\frac{0.76*0.24}{65}} = 0.8964

0.6236*100 = 62.36%

0.8964*100 = 89.64%

The 99% confidence interval is between 62.36%(lower bound) and 89.64%(upper bound).

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