Remark
You can find the answer to that by dividing any 2 consecutive terms putting the right one in the numerator and the left one in the denominator.
Forumula
ratio = right/left
right = - 8
left = 4
ratio = -8/4
ratio = -2
Any two numbers would work.
ratio = - 32/16 = - 2
Answer:
B.
6 red
6 blue
4 green
Step-by-step explanation:
6 red
6 blue
4 green
————-
16 total
4 green is 1/4 of 16 total so that is the correct probability.
Answer:
DL = 5.87 un.
LN = 10.98 un.
DN = 14.4 un.
Step-by-step explanation:
<u>Given:</u>
∆DLN,
LF ⊥ DN ,
DF = 4
m∠N = 23º,
m∠D = 47º
<u>Find:</u>
DL, LN, DN
Solution:
In right triangle DFL, DF = 4, m∠D = 47º, so
![LF=DF\tan \angle D\\ \\LF=4\cdot \tan 47^{\circ}\approx 4.29 \ units](https://tex.z-dn.net/?f=LF%3DDF%5Ctan%20%5Cangle%20D%5C%5C%20%5C%5CLF%3D4%5Ccdot%20%5Ctan%2047%5E%7B%5Ccirc%7D%5Capprox%204.29%20%5C%20units)
and
![DL=\dfrac{DF}{\cos \angle D}\\ \\DL=\dfrac{4}{\cos 47^{\circ}}\approx 5.87\ units](https://tex.z-dn.net/?f=DL%3D%5Cdfrac%7BDF%7D%7B%5Ccos%20%5Cangle%20D%7D%5C%5C%20%5C%5CDL%3D%5Cdfrac%7B4%7D%7B%5Ccos%2047%5E%7B%5Ccirc%7D%7D%5Capprox%205.87%5C%20units)
In right triangle LFN, LF = 4.29 units, m∠N = 23º, so
![FN=LF\cot \angle N\\ \\FN=4.29\cdot \cot 23^{\circ}\approx 10.11\ units](https://tex.z-dn.net/?f=FN%3DLF%5Ccot%20%5Cangle%20N%5C%5C%20%5C%5CFN%3D4.29%5Ccdot%20%5Ccot%2023%5E%7B%5Ccirc%7D%5Capprox%2010.11%5C%20units)
and
![LN=\dfrac{LF}{\sin \angle N}\\ \\LN=\dfrac{4.29}{\sin 23^{\circ}}\approx 10.98\ units](https://tex.z-dn.net/?f=LN%3D%5Cdfrac%7BLF%7D%7B%5Csin%20%5Cangle%20N%7D%5C%5C%20%5C%5CLN%3D%5Cdfrac%7B4.29%7D%7B%5Csin%2023%5E%7B%5Ccirc%7D%7D%5Capprox%2010.98%5C%20units)
Hence,
DN = 4.29 + 10.11 = 14.4 units
Answer:
![6.25](https://tex.z-dn.net/?f=6.25)
Step-by-step explanation:
![We\ are\ given:\\Observations\ in\ the\ Set=(7,5,4,9)\\ As\ we\ know\ that,\\ Average\ or\ interchangeably\ mean=\frac{Total\ Sum\ of\ observations }{Total\ no.\ of\ observations} \\Here,\\Total\ sum\ of\ the\ observations=7+5+4+9=25\\Total\ number\ of\ observations=4\\Hence\ here,\\Mean/Average=\frac{25}{4}=6.25](https://tex.z-dn.net/?f=We%5C%20are%5C%20given%3A%5C%5CObservations%5C%20in%5C%20the%5C%20Set%3D%287%2C5%2C4%2C9%29%5C%5C%20As%5C%20we%5C%20know%5C%20that%2C%5C%5C%20Average%5C%20or%5C%20interchangeably%5C%20mean%3D%5Cfrac%7BTotal%5C%20Sum%5C%20of%5C%20observations%20%7D%7BTotal%5C%20no.%5C%20of%5C%20observations%7D%20%5C%5CHere%2C%5C%5CTotal%5C%20sum%5C%20of%5C%20the%5C%20observations%3D7%2B5%2B4%2B9%3D25%5C%5CTotal%5C%20number%5C%20of%5C%20observations%3D4%5C%5CHence%5C%20here%2C%5C%5CMean%2FAverage%3D%5Cfrac%7B25%7D%7B4%7D%3D6.25)
Answer:
F (x) = 1,6
Step-by-step explanation:
my answer is due to the reason that it is one of the three options and it should only in a way make sense that it is the right answer