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morpeh [17]
2 years ago
12

Consider the reaction between a solution of molecule A and a solid block of molecule B. In general, for a reaction to occur, the

reactant molecules must be in contact with each other. Therefore, increasing the frequency of collisions between A and B molecules allows the reaction to occur more quickly. Identify the change in reaction condition that will increase the frequency of the molecular collisions.
Chemistry
1 answer:
Blababa [14]2 years ago
3 0

Answer:

Decreasing the volume of solvent in the solution of molecule A

Explanation:

We know that one of the factors that affect the rate of reaction is the concentration of the reactants. The greater the concentration of reactants, the faster the rate of reaction (the greater the frequency of collision between reactants).

Hence, when we decrease the volume of solvent in the solution of molecule A, the concentration of the solution increases and consequently more particles of molecule A are available to collide with particles of molecule B resulting in a higher rate of reaction.

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Explanation:

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3 years ago
A solution of which of the following coordination compounds will form a precipitate when treated with aqueous AgNO3?
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Answer:

[Cr(NH3)6.]C13

Explanation:

Alfred Werner's coordination theory (1893) recognized two kinds of valency;

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Hence, the number of counter ions precipitated from a complex depends on the primary valency of the central metal ion in the complex.

We must note that it is only these counter ions that occur outside the coordination sphere that can be precipitated by AgNO3.

If we consider the options carefully, only [Cr(NH3)6.]C13 possess counter ions outside the coordination sphere which can be precipitated when treated with aqueous AgNO3.

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2 years ago
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Explanation:

8 0
3 years ago
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Upper n subscript 2 (g) plus 3 upper H subscript 2 (g) double-headed arrow 2 upper N upper H subscript 3 (g). At equilibrium, th
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Answer:

The <u>equilibrium constant</u> is:

              k_c=0.0030M^{-2}

Explanation:

The correct equation is:

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Thus, with the equilibrium concentrations you can calculate the equilibrium constant, Kc.

The equation for the equilibrium constant is:

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Substituting:

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3 years ago
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