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sweet-ann [11.9K]
3 years ago
9

Pls help asap, this is due soon, brainliest

Chemistry
1 answer:
NemiM [27]3 years ago
4 0

The answer to this question is C hope I was fast enough

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2. Does the aluminum sample (the can) contain more than, (less than or exactly one mole of aluminum? Support answer with calcula
mrs_skeptik [129]

Answer:

than, (less than or exactly one mole

6 0
3 years ago
The periodic table is arranged by _______.
Goryan [66]

Answer: The atomic number

4 0
3 years ago
Read 2 more answers
Please help me what is the answer
Sladkaya [172]

There are 20.8 moles of propanol

<h3>Further explanation  </h3>

The mole is the number of particles(molecules, atoms, ions) contained in a substance  

1 mol = 6.02.10²³ particles

Can be formulated

N=n x No

N = number of particles

n = mol

No = Avogadro's = 6.02.10²³

1.2 x 10⁵ molecules of propanol

\tt \dfrac{1.25\times 10^{25}}{6.02\times 10^{23}}=20.8~moles

6 0
3 years ago
The second-order decomposition of NO2 has a rate constant of 0.255 M-15-1. How much NO2 decomposes in 4.00 s if the initial conc
S_A_V [24]

Answer:

Option D, Concentration of NO2 decomposes after 4.00 s = 0.77 mol

Explanation:

rate\;constant = 0.255\;M^{-1}s{-1}

Time (t) = 4.00\;s

Initial concentration of NO2 = 1.33 M

Integrated law for second order reaction:

\frac{1}{[A]}=\frac{1}{[A]_0} =kt

Where, [A] = Concentration after time, t

[A]0 = Intitial concentration, k = rate constant, t = time

On substituting values in the above

\frac{1}{[A]}=\frac{1}{1.33} =0.255 \times 4.00

\frac{1}{[A]} =1.772

[A] = 0.5644 M

Concentration of NO2 decomposes after 4.00 s = 1.33 - 0.5644 = 0.7656 M

No. of mole = Molarity * volume

                    = 0.7656 * 1

                    = 0.7656 mol 0r 0.77 mol

4 0
4 years ago
Use this data to graph temperature vs time<br>​
dangina [55]
What data are you showing ????
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3 years ago
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