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rjkz [21]
3 years ago
7

Which sequence does the energy transformation in an automobile engine.

Physics
1 answer:
Vera_Pavlovna [14]3 years ago
7 0

Answer:

Mechanical

Explanation:

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Does anyone know how to do this question???<br><br> Force = 7kN <br> Pressure = 1mPa<br> Area = ?
Andreas93 [3]

Answer:

7000 m^2

Explanation:

Pressure=Force/Area

1=7000/Area

1(Area)=7000

Area=7000 m^2

5 0
2 years ago
Two pucks collide with each other. after the collision they do not stick together. is kinetic energy conserved in the collision?
miv72 [106K]
Since they do not stick after collision hence collision is elastic. In elastic collision, both momentum and kinetic energy is conserved because in this type of collision, first body deforms but then quickly regains its former shape and transfers its kinetic energy to the second pluck.
So kinetic energy is conserved.
5 0
3 years ago
A 5000.0-kg car goes from 0 m/s to 70 m/s in 3600 seconds. What is the accelera
antiseptic1488 [7]

given:

mass = 5000 kg

u (initial velocity) = 0 m/s

v (final velocity) = 70 m/s

time taken to change velocity = 3600 s

acceleration = v - u / t

a = 70 - 0 / 3600

a = 70 / 3600

a =  0.0194 m/s2 (approx)

given: mass = 5000 kg

acceleration = 0.0194 (found in 1st part)

force = mass * acceleration

f = ma

f = 5000*0.0194 = 97 N

therefore the acceleration will be 0.0194 m/s2

and the force involved in acceleration will be 97 N

4 0
2 years ago
The fully loaded bus accelerates uniformly from rest to a speed of 14 m / s. The time taken to reach a speed of 14 m / s is 20 s
tino4ka555 [31]

Answer:

0.7m/s^2

Explanation:

acceleration=(final-initial velocity)/time

x=(14-0)/20

x=14/20

x=0.7

3 0
3 years ago
Light of wavelength 600nm illuminates a diffraction grating. The second-order maximum is at angle 39°. How many lines per millim
fomenos

Answer:

the number of lines is 526

Explanation:

The wavelength  λ =600nm = 600 × 10⁻⁶ mm

The diffraction angle θ = 39°

Recall the expression for the relation between the wavelength, angle and central maxima distance.

Recall the expression for the relation between the wavelength, angle and central maxima distance.

Recall the expression for the relation between the wavelength, angle and central maxima distance.

relation between the wave length, angle and central maxima distance

d =  nλ / sinθ

Here n = 2 for second order maxima and d is the distance

= 2(600 × 10⁻⁶) / sin 39°

= 1200 × 10⁻⁶ / 0.6293

= 1.9 × 10⁻³ mm

N = 1/d

= 1 / 1.9 × 10⁻³

= 526

The grating has a line density of 526 lines per millimeter

3 0
3 years ago
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