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3 years ago

Hellllppppppp please

Physics

1 answer:

WITCHER [35]3 years ago

3 0

I hope that helps! Let me know if you need any more help!

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Conclusion for ohm law

kari74 [83]

Ohm’s Law states that electrical current is proportional to voltage and therefore inversely proportional to resistance - V = I x R

7 0

3 years ago

A 4.00-kg mass is attached to a very light ideal spring hanging vertically and hangs at rest in the equilibrium position. The sp

Ahat [919]

Answer:

|v| = 8.7 cm/s

Explanation:

given:

mass m = 4 kg

spring constant k = 1 N/cm = 100 N/m

at time t = 0:

amplitude A = 0.02m

unknown: velocity v at position y = 0.01 m

$y = A cos(\omega t + \phi)\\v = -\omega A sin(\omega t + \phi)\\ \omega = \sqrt{\frac{k}{m}}$

1. Finding Ф from the initial conditions:

$-0.02 = 0.02cos(0 + \phi) => \phi = \pi$

2. Finding time t at position y = 1 cm:

$0.01 =0.02cos(\omega t + \pi)\\ \frac{1}{2}=cos(\omega t + \pi)\\t=(acos(\frac{1}{2})-\pi)\frac{1}{\omega}$

3. Find velocity v at time t from equation 2:

$v =-0.02\sqrt{\frac{k}{m}}sin(acos(\frac{1}{2}))$

5 0

3 years ago

Read 2 more answers

A snowboarder starts from rest on an inclined planar snow surface and gives herself a tiny push to start sliding down the hill.

tiny-mole [99]

Answer:

v = 26.52 m/s

Explanation:

Here we know that as she passes the flag she will gain some speed

so here we can say that

Work done by all forces = change in kinetic energy of the system

so we will have

$W_g + W_f = \frac{1}{2}mv_f^2 - \frac{1}{2}mv_i^2$

here we know that

$W_g = mgh$

$W_f = -\mu mg d$

$v_i = 0$

h = 39.78 m

d = 27.81 m

so we have

$mgh - \mu mg d = \frac{1}{2}mv^2 - 0$

$(9.8)(39.78 - (0.14)(27.81)) = \frac{1}{2} v^2$

$v = 26.52 m/s$

8 0

3 years ago

The equation that describes a transverse wave on a string is y = (0.0120 m)sin[(927 rad/s)t - (3.00 rad/m)x] where y is the disp

dem82 [27]

Answer:

Speed, v = 312.34 m/s

Explanation:

The equation that describes a transverse wave on the string is given by :

$y=0.0120\ msin[(927\ rad/s)t-(3\ rad/m)x]$ ..............(1)

Where

y = displacement of a string particle

x = position of the particle on the string

The wave is travelling in the +x direction. We have to find the speed of the wave.

The general equation of traverse wave is given by :

$y=A\ sin(kx-\omega t)$ ................(2)

On comparing equation (1) and (2) we get,

k = 3 rad/m

Since, $k=\dfrac{2\pi}{\lambda}$

$\lambda=\dfrac{2\pi}{3}$ ..............(3)

Also, $\omega=927\ rad/s$

Since, $\omega=2\pi \nu$

$\nu=\dfrac{927}{2\pi}$ ...............(4)

Speed of the wave is the product of frequency and wavelength i.e.

$v=\nu\times \lambda$

Using equation (3) and (4), the speed of the wave can be calculated as :

$v=\dfrac{927}{2\pi}\times \dfrac{2\pi}{3}$

v = 312.34 m/s

Hence, the speed of the transverse wave is 312.34 m/s

5 0

3 years ago

Sally's mass on Earth is 50 kg. What is her weight on Earth?

Anarel [89]

Answer490N:

Explanation:

8 0

3 years ago