PLEASE HELP WITH QUESTION #5!!!!

Chemistry

1 answer:

vagabundo [1.1K]3 years ago

8 0

Answer: 2.008 g

Explanation:

we can use the similar equations as I have before: q = mcAT

we are given q, AT, and c is a constant so now we have to solve for m

84=m(4.184)(10)

m = 2.008 g of water

You might be interested in

Classify each of these soluble solutes as a strong electrolyte, a weak electrolyte, or a nonelectrolyte. Solutes formula hydroch

matrenka [14]

Compounds which on dissolving in water gets completely dissociates into its ions are known as strong electrolytes whereas compounds which on dissolving in water gets partially dissociates into its ions are known as weak electrolytes.

Substances which gives solution on dissolving in water and do not dissociates into ions also does not conduct electric current are known as nonelectrolyte.

Hydrochloric acid, $HCl$

On adding $HCl$ (strong acid) in water, it will completely dissociates into ions ( $H^{+}$ and $Cl^{-}$ ) and thus, it is a strong electrolyte.

Sodium hydroxide, $NaOH$

On adding $NaOH$ (strong base) in water, it will completely dissociates into ions ( $Na^{+}$ and $OH^{-}$ ) and thus, it is a strong electrolyte.

Formic acid, $HCOOH$

On adding $HCOOH$ (weak acid) in water, it will partially dissociates into ions ( $H^{+}$ and $HCOO^{-}$ ) and thus, it is a weak electrolyte.

Methyl amine, $CH_3NH_2$

On adding $CH_3NH_2$ (weak base) in water, it will partially dissociates into ions ( $CH_3NH_3^{+}$ and $OH^{-}$ ) and thus, it is a weak electrolyte.