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3 years ago

Why does water from a flat plate disappears quickly but not from a bucket full of water when both are kept in bright sunshine?

Chemistry

1 answer:

Lera25 [3.4K]3 years ago

6 0

Answer:

water in the flat plate is less so it takes lesser time to disappear

Explanation:

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Distinguish and give example for homogeneous and heterogeneous mixture

Nataliya [291]

Answer:

Through combining two or more substances, a mixture is produced. A homogeneous solution tends to be identical, no matter how you sample it. Homogeneous mixtures are sources of water, saline solution, some alloys, and bitumen. Sand, oil and water, and chicken noodle soup are examples of heterogeneous mixtures.

Explanation:

6 0

3 years ago

You have 125 g of a certain seasoning and are told that it contains 48.0 g of salt. what is the percentage of salt by mass in th

juin [17]

There is 38.4 % of salt by mass

4 0

3 years ago

What is not a typical step when performing scientific research

Gelneren [198K]

The six steps of the scientific are:

1. State the question

2. Conduct research

3. Create a hypothesis

4. Perform the experiment

5. Analyze the data

6. Conclusion

So D. would be the correct answer, even though communicating the results could possibly be a step if it's required.

8 0

3 years ago

4. Magnesium and oxygen undergo a chemical reaction to

erastovalidia [21]

Answer:

About 16.1 grams of oxygen gas.

Explanation:

The reaction between magnesium and oxygen can be described by the equation:
$\displaystyle 2\text{Mg} + \text{O$_2$} \longrightarrow 2\text{MgO}$

24.4 grams of Mg reacted with O₂ to produce 40.5 grams of MgO. We want to determine the mass of O₂ in the chemical change.

Compute using stoichiometry. From the equation, we know that two moles of MgO is produced from every one mole of O₂. Therefore, we can:

Convert grams of MgO to moles of MgO.
Moles of MgO to moles of O₂
And moles of O₂ to grams of O₂.

The molecular weights of MgO and O₂ are 40.31 g/mol and 32.00 g/mol, respectively.

Dimensional analysis:

$\displaystyle 40.5\text{ g MgO} \cdot \frac{1\text{ mol MgO}}{40.31\text{ g MgO}} \cdot \frac{1\text{ mol O$_2$}}{2\text{ mol MgO}} \cdot \frac{32.00\text{ g O$_2$}}{1\text{ mol O$_2$}} = 16.1\text{ g O$_2$}$

In conclusion, about 16.1 grams of oxygen gas was reacted.

You will obtain the same result if you compute with the 24.4 grams of Mg instead:

$\displaystyle 24.4\text{ g Mg}\cdot \frac{1\text{ mol Mg}}{24.31\text{ g Mg}} \cdot \frac{1\text{ mol O$_2$}}{1\text{ mol Mg}} \cdot \frac{32.00\text{ g O$_2$}}{1\text{ mol O$_2$}} = 16.1\text{ g O$_2$}$

3 0

2 years ago

Please help on this one?

quester [9]

Answer:

the answer is= NUCLEAR FISSION, NUCLEAR FUSSION, RADIOACTIVE DECAY.

7 0

4 years ago

Read 2 more answers