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raketka [301]
3 years ago
14

The osmotic pressure exerted by a solution is equal to the molarity multiplied by the absolute temperature and the gas constant

RSuppose the osmotic pressure of a certain solution is measured to be 22.atm at an absolute temperature of 353.KWrite an equation that will let you calculate the molarity c of this solution. Your equation should contain only symbols. Be sure you define each symbol other than R.
Chemistry
1 answer:
zavuch27 [327]3 years ago
7 0

Answer: M = 22/ (i x28.948)

Explanation:

Pi = osmotic pressure = 22atm

T = Temperature = 353K

M = Molarity = ?

R = gas constant = 0.082atm.L/mol/K

i = van’t Hoff factor

Pi = iMRT

M= Pi /(iRT) = 22 / ( i x 0.082 x 353)

M = 22/ (i x28.948)

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<h3>Answer:</h3>

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<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

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  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
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<u>Chemistry</u>

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<h3>Explanation:</h3>

<u>Step 1: Define</u>

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<u>Step 2: Identify Conversions</u>

Molar Mass of K - 39.10 g/mol

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Molar Mass of K₃N - 3(39.10) + 14.01 = 131.31 g/mol

<u>Step 3: Convert</u>

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<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We are given 3 sig figs.</em>

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