We have to get the amount of nitrogen to be consumed to get 0.75 moles of ammonia.
The amount of nitrogen (in grams) required to prepare 0.75 moles of ammonia is: 10.5 grams.
Ammonia (NH₃) can be prepared from nitrogen (N₂) as per following balanced chemical reaction-
N₂ (g) + 3H₂ (g) ⇄ 2NH₃ (g)
According to the above reaction, to prepare 2 moles of ammonia, one mole of nitrogen is required. Hence, to prepare 0.75 moles of ammonia, 
moles = 0.375 moles of nitrogen is required.
Molar mass of nitrogen is 28 grams, i.e, mass of one mole of nitrogen is 28 grams, so mass of 0.375 moles of nitrogen is 0.375 X 28 grams=10.5 grams of nitrogen.
Therefore, the amount of nitrogen (in grams) required to prepare 0.75 moles of ammonia is 10.5 grams.
Answer: an arithmetical multiplier for converting a quantity expressed in one set of units into an equivalent expressed in another.
Explanation:
Answer:
A
Explanation:
Because the amount of electrons in the outer shell can be a maximum of 8
Hope this helps
Answer:
I believe that zombies are not living
Explanation:
because zombies don't grow and develop because they are practically mindless. Also, zombies definitely respond to the environment (like when they see a human) but they don't adapt to it
Answer:
The Ideal gas law
Explanation:
From the given question, we have:
V 
where each variable has its usual meaning.
Thus,
V = 
where R is the ideal gas constant
cross multiply to have;
PV = nRT
This implies that the volume of the gas is directly proportional to the number of moles of the gas.
Therefore, the law can be used to determine the relationship between the volume and number of moles is the ideal gas law.
