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4 years ago

8

As we move from left to right across the periodic table, what is the general trend? A) Atomic radii increase. B) Electronegaviti

y decreases. C) Nuclear shielding increases. D) Metallic character decreases.

2 answers:

inysia [295]4 years ago

5 0

Answer:

So it was D?

Thanks

Explanation:

elena55 [62]4 years ago

4 0

B. Electronegavitiy decreases

Electron affinity decreases as we proceed down a group.

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What is the theoretical yield of vanadium, in moles, that can be produced by the reaction of 1.0 mole of V2O5 with 4.0 mole of c

yuradex [85]

Answer:

Theoretical moles of V are 1.6 moles

Explanation:

The theoretical yield of a reaction is defined as the amount of product you would make if all of the limiting reactant was converted into product.

In the reaction:

V2O5(s) + 5Ca(i) → 2V(i) + 5CaO(s)

Based on the reaction, 1 mol of V2O5 needs 5 moles of Ca for a complete reaction. As there are just 4 moles, <em>limiting reactant is Ca.</em> As there are produced 2 moles of V per 5mol of Ca, Theoretical moles of V are:

4 moles of Ca × (2mol V / 5Ca) = <em>1.6 moles of V</em>

<em></em>

I hope it helps!

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3 years ago

You need to produce a buffer solution that has a pH of 5.26. You already have a solution that contains 10. mmol (millimoles) of

Andreas93 [3]

The question is incomplete, complete question is :

You need to produce a buffer solution that has a pH of 5.50. You already have a solution that contains 10 mmol (millimoles) of acetic acid. How many millimoles of acetate (the conjugate base of acetic acid) will you need to add to this solution? The pka of acetic acid is 4.74.

Answer:

33.11 millimoles of acetate we will need to add to this solution.

Explanation:

To calculate the pH of acidic buffer, we use the equation given by Henderson Hasselbalch:

$pH=pK_a+\log(\frac{[salt]}{[acid]})$

Where :

tex]pK_a[/tex] = negative logarithm of acid dissociation constant of acid

[salt] = Concentration of salt

[Acid] = Concentration of salt

We have:

pH = 5.26

$pK_a=4.74$

[salt] = $[CH_3COO^-]$ = ?

[acid] = $[CH_3COOH]=10.0 mmol$

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$[CH_3COO^-]=33.11 mmol$

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sveticcg [70]

Answer:

I don't see any of the following. If you could possibly tell me what the following answers are in the comments I can help :)

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MAXImum [283]

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