Yes, the ones that make of the atom itself. The proton which is a positive charge which has most of the weight of the atom and is found in the nucleus. The neutron which weighs almost nothing has a neutral charge and is found in the nucleus with the protons. Lastly the electrons which have a negative charge and orbit the atom in the electron cloud around the nucleus and also weigh very little.
Answer:
The empirical formula of the compound is = 
The name of the compound is potassium bromate.
Explanation:
Mass of potassium = 4.628 g
Moles of potassium = 
Mass of bromine = 9.457 g
Moles of bromine = 
Mass of oxygen = 5.681 g
Moles of oxygen = 
For empirical formula of the compound, divide the least number of moles from all the moles of elements present in the compound:
Potassium :
Bromine;
Oxygen ;
The empirical formula of the compound is =
The name of the compound is potassium bromate.
Answer:
I think it's either A or D I'm not sure hope that I helped you.
Answer:
6Br⁻ + XeO₃ + 6H⁺ → 3Br₂ + Xe + 3H₂O
Explanation:
First, we need to write the half-reactions:
2Br⁻ → Br₂ + 2e⁻ Oxidation -Balanced yet-
XeO₃ → Xe Reduction
To balance the reduction in acidic aqueous solution we need to add waters in the other side of the reaction as oxygens are present:
XeO₃ → Xe + 3H₂O
And H⁺ as hydrogens from water we have:
XeO₃ + 6H⁺ → Xe + 3H₂O
To balance the charge:
<h3>XeO₃ + 6H⁺ + 6e⁻ → Xe + 3H₂O Reduction -Balanced-</h3><h3 />
To cancel out the electrons of both half-reaction we need to multiply oxidation 3 times:
6Br⁻ → 3Br₂ + 6e⁻
XeO₃ + 6H⁺ + 6e⁻ → Xe + 3H₂O
And the balanced reaction in acidic aqueous solution is the sum of both half-reactions:
<h3>6Br⁻ + XeO₃ + 6H⁺ → 3Br₂ + Xe + 3H₂O </h3>
Answer:
A. 3.5ml
Explanation:
lowest point of liquid or meniscus
