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weqwewe [10]
3 years ago
14

Choose the substance with the highest surface tension.

Chemistry
1 answer:
umka2103 [35]3 years ago
8 0

Answer:

Hello

you're answer should be E.HOCH2CH2OH

hope this answer is correct

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For a particular isomer of C8H18, the combustion reaction produces 5113.3 kJ of heat per mole of C8H18(g) consumed, under standa
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Answer: The standard enthalpy of formation of this isomer of C_8H_{18}(g) is -210.9 kJ

Explanation:

The given balanced chemical reaction is,

C_8H_{18}(g)+\frac{25}{2}O_2(g)\rightarrow 8CO_2(g)+9H_2O(g)

First we have to calculate the enthalpy of formation of  C_8H_{18}.

\Delta H^o=H_f_{product}-H_f_{reactant}

\Delta H^o=[n_{CO_2}\times \Delta H_f^0_{(CO_2)}+n_{H_2O}\times \Delta H_f^0_{(H_2O)}]-[n_{O_2}\times \Delta H_f^0_{(O_2)+n_{C_8H_{18}}\times \Delta H_f^0_{(C_8H_{18})}]

where,

We are given:

\Delta H^o_f_{(CO_2(g))}=-393.5kJ/mol\\\Delta H^o_f_{(H_2O(g))}=-241.8kJ/mol\\\Delta H^o_f_{(O_2(g)))}=0kJ/mol

Putting values in above equation, we get:

-511.3kJ/mol=[(8\times -393.5)+(9\times -241.8)]-[(\frac{25}{2}\times 0)+(1\times \Delta H_f^0_{(C_8H_{18})}

\Delta H_f^0_{(C_8H_{18})}=-210.9kJ

7 0
4 years ago
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