Answer:
500 N
Explanation:
Given;
Mass of the car, M = 1000 kg
initial speed of the car, u = 0 m/s
Final speed of the car, v = 60 m/s
Time, t = 1 min = 60 s
Now,
Force, F is given as:
F = Ma
where,
a is the acceleration
From the Newton's equation of motion, we have
v = u + at
on substituting the values, we get
60 = 0 + a × 60
or
a = 1 m/s²
Thus,
Force = 1000 × 1 = 1000 N
now,
this force will be equal to the friction force provided by the rear wheels
let the friction force on a single rear wheel be 'f'
thus,
2f = 1000 N
or
f = 500 N
Answer:
Hello, I'm good. Thank you for asking
Answer:
The statement is as follows:
Explanation:
We had better avoid such correlated subqueries by instead using aggregation with GROUP BY:
SELECT
c.email_address,
COUNT(DISTINCT o.order_id) AS num_orders,
COALESCE(SUM(oi.quantity * (oi.item_price - oi.discount_amount)), 0) AS total_amount
FROM customers c
LEFT JOIN orders o
ON c.customer_id = o.customer_id
INNER JOIN order_items oi
ON o.order_id = oi.order_id
GROUP BY
c.customer_id,
c.email_address;
