Find the equivalent impedance Zeq seen by the source when Vs = 2 cos (5t) v, C = 0.2 F, R = 1 Ω and L = 0.1 H. (Give angles in d
egrees and round final answers to two decimal places.) Calculate the voltage across the resistor. (Give angles in degrees and round final answers to two decimal places.) complex impedance The equivalent impedance seen by the source is + j Ω = at an angle of Ω. The voltage across the resistor is at an angle of v.
1 answer:
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Answer:
Explanation:
Given data in question
mean stress = 50 MPa
amplitude stress = 225 MPa
to find out
maximum stress, stress ratio, magnitude of the stress range.
solution
we will find first maximum stress and minimum stress
and stress will be sum of (maximum +minimum stress) / 2
so for stress 50 MPa and 225 MPa
=
+
/ 2
50 = +
/ 2 ...........1
and
225 = +
/ 2 ...........2
from eqution 1 and 2 we get maximum and minimum stress
= 275 MPa ............3
and = -175 MPa ............4
In 2nd part we stress ratio is will compute by ratio of equation 3 and 4
we get ratio = /
ratio = -175 / 227
ratio = -0.64
now in 3rd part magnitude will calculate by subtracting maximum stress - minimum stress i.e.
magnitude = -
magnitude = 275 - (-175) = 450 MPa
Answer:
The electrical power is 96.5 W/m^2
Explanation:
The energy balance is:
Ein-Eout=0
if:
Gsky=oTsky^4
Eb=oTs^4
qc=h(Ts-Tα)
if Gl≈El(l,5800)
lt= 2*5800=11600 um-K, at this value, F=0.941
The hemispherical emissivity is equal to:
lt=2*333=666 K, at this value, F=0
The hemispherical absorptivity is equal to: