Find the equivalent impedance Zeq seen by the source when Vs = 2 cos (5t) v, C = 0.2 F, R = 1 Ω and L = 0.1 H. (Give angles in d
egrees and round final answers to two decimal places.) Calculate the voltage across the resistor. (Give angles in degrees and round final answers to two decimal places.) complex impedance The equivalent impedance seen by the source is + j Ω = at an angle of Ω. The voltage across the resistor is at an angle of v.
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Answer:
The answer to the question above is = 152.02 KJ/Kg
Explanation:
Given:
Temperature at first state, (T)= 500k
Temperature at second state, (T)= 500k
The above explains an isothermal process as a thermodynamic process,in which the temperature of the system remains constant
Pressure at first state, (p) = 10 bar
Pressure at second state, (p) = 2 bar
The heat transfer=
Qrev/m= T x [s(T) - s(T
) - R ㏑ (p
÷ p
)]
Isothermal means the temperature does not change, while Expansion means the volume has increased.
For the internal isothermal process:
Qrev/m= T x [- R ㏑ (p ÷ p
)]
= 500 x - (8.314 ÷ 44.01) x In (2 ÷ 10) = 152.02 KJ/Kg
Energy equation at turbine is for the internally reversible isothermal process is:
Q-w = m [( (V²- V
²) ÷ 2) + g ( Z
- Z
)]
where w= the most efficient work possible in J
Neglecting the effect of both potential and kinetic energy
(w/ m) = Qrev/ m
= 152.02 KJ/Kg