Answer:
<em>(a) t = 4.52 sec</em>
<em>(b) X = 1,156.49 m</em>
Explanation:
<u>Horizontal Launching
</u>
If an object is launched horizontally, its initial speed is zero in the y-coordinate and the horizontal component of the velocity
remains the same in time. The distance x is computed as
.
(a)
The vertical component of the velocity
starts from zero and gradually starts to increase due to the acceleration of gravity as follows

This means the vertical height is computed by

Where
is the initial height. Our fighter bomber is 100 m high, so we can compute the time the bomb needs to reach the ground by solving the above equation for t knowing h=0


(b)
We now compute the horizontal distance knowing 

V=IR can be changed to V/R=I so 10V/2 ohms = 5amps so 5 amps is your answer boss
Answer:
B. Attract each other with a force of 10 newtons.
Explanation:
Statement is incorrectly written. <em>The correct form is: A </em>
<em> charge and a </em>
<em> at a distance of 0.3 meters. </em>
The two particles have charges opposite to each other, so they attract each other due to electrostatic force, described by Coulomb's Law, whose formula is described below:
(1)
Where:
- Electrostatic force, in newtons.
- Electrostatic constant, in newton-square meters per square coulomb.
- Magnitudes of electric charges, in coulombs.
- Distance between charges, in meters.
If we know that
,
and
, then the magnitude of the electrostatic force is:


In consequence, correct answer is B.
Answer:
1.86 m
Explanation:
First, find the time it takes to travel the horizontal distance. Given:
Δx = 52 m
v₀ = 26 m/s cos 31.5° ≈ 22.2 m/s
a = 0 m/s²
Find: t
Δx = v₀ t + ½ at²
52 m = (22.2 m/s) t + ½ (0 m/s²) t²
t = 2.35 s
Next, find the vertical displacement. Given:
v₀ = 26 m/s sin 31.5° ≈ 13.6 m/s
a = -9.8 m/s²
t = 2.35 s
Find: Δy
Δy = v₀ t + ½ at²
Δy = (13.6 m/s) (2.35 s) + ½ (-9.8 m/s²) (2.35 s)²
Δy = 4.91 m
The distance between the ball and the crossbar is:
4.91 m − 3.05 m = 1.86 m
<span>3.2x10^-2 seconds (0.032 seconds)
This is a simple matter of division. I also suspect it's an exercise in scientific notation, so here is how you divide in scientific notation:
9.6 x 10^6 m / 3x10^8 m/s
First, divide the significands like you would normally.
9.6 / 3 = 3.2
And subtract the exponent. So
6 - 8 = -2
So the answer is 3.2 x 10^-2
And since the significand is less than 10 and at least 1, we don't need to normalize it.
So it takes 3.2x10^-2 seconds for the radio signal to reach the satellite.</span>