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ruslelena [56]
3 years ago
12

Which of the following equations represents an acid base reaction?

Physics
2 answers:
lana [24]3 years ago
6 0
2nd one would be the answer
Lina20 [59]3 years ago
4 0

Answer:

the second one

Explanation:

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In a given system of units the ratio of the unit of volume to that of area gives the unit of​
ch4aika [34]

Answer:

length

Explanation:

SI unit of volume = m^3

SI unit of area = m^2

volume unit / Area unit = m^3 / m^2

i.e, unit of length

8 0
2 years ago
A football player who weighs 550 N stands indoors wearing her football boots. The boot’s
EleoNora [17]

Answer:

183333 Pa

Explanation:

The weight of the football player is : 550 N ,thus the force the player exerts on the floor is 550 N

The area of blades in contact with the floor is = 30cm² = 0.003 m²

Pressure = Force / Area

Pressure = 550 / 0.003

Pressure = 183333 Pa

3 0
2 years ago
A 50 Kg box sits at rest on a 30 degree ramp where the coef of static friction is 0.5773. If your push was directed at an angle
emmasim [6.3K]

<u>Given data:</u>

m= 50 Kg,

W= m×g = 50 × 9.81 = 490.5 N

ramp angle (α) = 30 degrees,

coefficient of friction (μs) = 0.5773,

Push at an angle (Θ) = 40 degrees,

Determine: Push to get box move up (P)=?

From the figure,

Resolving the forces along the plane

W sinα + μs.R = P cos Θ       --------------------- (i)

Resolving the forces perpendicular to the inclined plane

W cosα = R+Psin Θ  =>  R= W cosα - Psin Θ -------------- (ii)

Solving (i) and (ii) and keeping <em>μs = tan Φ, Φ = Θ </em>

<em>Pmin = W sin( α +Θ  )</em>

<em>          = W[ sin α.Cos Θ + cos α.sin Θ]</em>

<em>           = 490.5 [ (sin 30.cos40) + (cos30.sin 40)]</em>

<em>           = 460.9 N</em>

<em>Minimum push required to move the box up the ramp is 460.9 N</em>


7 0
3 years ago
Peak hydraulic systems demands may be met by the use of what ?
nikklg [1K]
By the use of a Accumulators
8 0
3 years ago
Read 2 more answers
At about 55 meters/sec, a falling parachuter (before the parachute opens) no longer accelerates. Air friction opposes accelerati
JulijaS [17]
The acceleration of gravity on Earth is about 9.8 m/s².
That means that if air resistance is neglected, a falling body
smoothly gains 9.8 m/s of downward speed each second.

If our intrepid chutist lightly stepped out of the plane or was
gently pushed, so that his initial downward speed was zero
and grew by 9.8 m/s every second, then it took him ...

               (55) / (9.8)  =  5.6 seconds

to reach that particular downward speed.
3 0
3 years ago
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