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Aleksandr [31]
3 years ago
9

Can someone help me with these two? Pls

Physics
1 answer:
Gelneren [198K]3 years ago
8 0
For the first one: A falling object has higher gravitational potential energy and as it falls this decreases but kinetic energy increases. As the object hits the floor, energy is transferred to heat and sound.

42*9.8*12= 4939.2
Kinetic energy = 4939.2 OR 4939

To find the final speed use the kinetic energy formula;

Ek = 1/2 MV2

4939=1/2*42*v2
V2= 4939 divided by (1/2 * 42)
V2= 4939 / 21
V2= 235.1904761904762
Find square root
V= 15.3359211067
= 15.

Reach the ground at 15m s -¹


Note:
Formula To calculate kinetic energy:
Ek = 1/2 MV2
Ek= kinetic energy of an object
M= mass of object
V= velocity/speed of object

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A 0.250 kg block attached to a light spring oscillates on a frictionless, horizontal table. The oscillation amplitude is A = 0.1
bulgar [2K]

The spring constant, k will be 18 N/m.The ratio of force to one unit of displaced length is known as the spring constant.

<h3>What is the spring constant?</h3>

Spring constant is defined as the ratio of force per unit displaced length.

Given data;

Mass of  block,m=0.250 k

Amplitude,A = 0.125 m

Velocity,V=3.00 m/

Spring constant,K=?

The formula for the spring constant when the spring is oscillate at the given amplitude A:

\rm K = \frac{V_{max}^2 m}{A} \\\\  K = \frac{3.0 \times 0.250}{0.125} \\\\ K=18 \ N/m

Hence, the spring constant, k will be 18 N/m

To learn more about the spring constant, refer:

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Newton's First Law states that an object will remain at rest or in uniform motion in a straight line unless acted upon by an external force.

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What is the power generated by a 45 kg person who walks up a flight of 12 stairs, each 30 cm high, in 12 s?
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The total distance covered by the person is 12 times the height of each stair:
\Delta h=12 \cdot 30 cm=360 cm=3.60 m

The work done by the person to climb the stairs is equal to the increase in his gravitational potential energy:
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And therefore, the power generated by the person in 12 s is the work done divided by the time taken:
P= \frac{W}{t}= \frac{1589.2 J}{12 s}=132.3 W

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added to the engine minus the waste heat

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The amount of work done by a heat engine equals the amount of thermal energy added to the engine minus the waste heat.

Thermodynamics is used to measure the energy changes that accompanies physical and chemical process.

 In a system;

  Internal energy = Quantity of heat added - Work done on it

 internal energy is designated as ΔU

  quantity of heat as Q

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                ΔU = Q - W

  so       W = Q  -   ΔU

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