To solve this equation simply find 2 numbers that multiply to give -4 and add also to give 3, these numbers are 4 and -1. Since 4 • -1 = -4 and 4 + -1 = 3.
X^2 + 3x - 4 = 0
(X - 1)(X + 4) = 0
X = -4 and X = 1 in ascending order.
The computation shows that the placw on the hill where the cannonball land is 3.75m.
<h3>How to illustrate the information?</h3>
To find where on the hill the cannonball lands
So 0.15x = 2 + 0.12x - 0.002x²
Taking the LHS expression to the right and rearranging we have:
-0.002x² + 0.12x -.0.15x + 2 = 0.
So we have -0.002x²- 0.03x + 2 = 0
I'll multiply through by -1 so we have
0.002x² + 0.03x -2 = 0.
This is a quadratic equation with two solutions x1 = 25 and x2 = -40 since x cannot be negative x = 25.
The second solution y = 0.15 * 25 = 3.75
Learn more about computations on:
brainly.com/question/4658834
#SPJ4
Complete question:
The flight of a cannonball toward a hill is described by the parabola y = 2 + 0.12x - 0.002x 2 . the hill slopes upward along a path given by y = 0.15x. where on the hill does the cannonball land?
Step-by-step explanation:
Let x represent theta.
Using the angle addition trig formula,
Multiply one side at a time
Replace theta with x , the answer is
2. Convert 30 degrees into radian
Using tangent formula,
Tan if pi/6 is sqr root of 3/3
Since my phone about to die if you later simplify that,
you'll get
Replace theta with X.
1.) 376.2
2.) 37620
3.)376200.
3.) 3762000
hope that helped
