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3 years ago

What is equivalent to 32

Mathematics

2 answers:

Norma-Jean [14]3 years ago

8 0

32.0, 64/2, 1/32 and probably 32/1

frez [133]3 years ago

4 0

Answer:

32.0 or 32/1 or 64/2

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Use the laplace transform to solve the given initial-value problem. y' 5y = e4t, y(0) = 2

Basile [38]

The Laplace transform of the given initial-value problem

$y' 5y = e^{4t}, y(0) = 2$ is mathematically given as

$y(t)=\frac{1}{9} e^{4 t}+\frac{17}{9} e^{-5 t}$

<h3>What is the Laplace transform of the given initial-value problem? y' 5y = e4t, y(0) = 2?</h3>

Generally, the equation for the problem is mathematically given as

$&\text { Sol:- } \quad y^{\prime}+s y=e^{4 t}, y(0)=2 \\\\&\text { Taking Laplace transform of (1) } \\\\&\quad L\left[y^{\prime}+5 y\right]=\left[\left[e^{4 t}\right]\right. \\\\&\Rightarrow \quad L\left[y^{\prime}\right]+5 L[y]=\frac{1}{s-4} \\\\&\Rightarrow \quad s y(s)-y(0)+5 y(s)=\frac{1}{s-4} \\\\&\Rightarrow \quad(s+5) y(s)=\frac{1}{s-4}+2 \\\\&\Rightarrow \quad y(s)=\frac{1}{s+5}\left[\frac{1}{s-4}+2\right]=\frac{2 s-7}{(s+5)(s-4)}\end{aligned}$

$\begin{aligned}&\text { Let } \frac{2 s-7}{(s+5)(s-4)}=\frac{a_{0}}{s-4}+\frac{a_{1}}{s+5} \\&\Rightarrow 2 s-7=a_{0}(s+s)+a_{1}(s-4)\end{aligned}$

$put $s=-s \Rightarrow a_{1}=\frac{17}{9}$$

$\begin{aligned}\text { put } s &=4 \Rightarrow a_{0}=\frac{1}{9} \\\Rightarrow \quad y(s) &=\frac{1}{9(s-4)}+\frac{17}{9(s+s)}\end{aligned}$

In conclusion, Taking inverse Laplace tranoform

$L^{-1}[y(s)]=\frac{1}{9} L^{-1}\left[\frac{1}{s-4}\right]+\frac{17}{9} L^{-1}\left[\frac{1}{s+5}\right]$ \\\\$

$y(t)=\frac{1}{9} e^{4 t}+\frac{17}{9} e^{-5 t}$

Read more about Laplace tranoform

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6 0

1 year ago

In a triangle angle a=40 angle b= 45 angle c= 90 find angle of x

cluponka [151]

Answer:angle x=5

Step-by-step explanation:

Sum of triangles =180 ,x+90+45+40=180, x+175=180 ,x =5

6 0

3 years ago

7. Which of the following can be determined from the graph below?

tatyana61 [14]

Answer:

The ordered pair (6,25) is a solution to both

$y=-\frac{5}{2}x+40$ and $y=\frac{5}{3}x+15$

Step-by-step explanation:

Part 7)

step 1

Find the equation of the line with positive slope

take the points (0,15) and (9,30)

Find the slope

The formula to calculate the slope between two points is equal to

$m=\frac{y2-y1}{x2-x1}$

substitute the given values

$m=\frac{30-15}{9-0}$

$m=\frac{15}{9}$

simplify

$m=\frac{5}{3}$

Find the equation of the line in slope intercept form

$y=mx+b$

we have

$m=\frac{5}{3}$

$b=15$

substitute

$y=\frac{5}{3}x+15$

step 2

Find the equation of the line with negative slope

take the points (0,40) and (8,20)

Find the slope

The formula to calculate the slope between two points is equal to

$m=\frac{y2-y1}{x2-x1}$

substitute the given values

$m=\frac{20-40}{8-0}$

$m=-\frac{20}{8}$

simplify

$m=-\frac{5}{2}$

Find the equation of the line in slope intercept form

$y=mx+b$

we have

$m=-\frac{5}{2}$

$b=40$

substitute

$y=-\frac{5}{2}x+40$

step 3

Find the solution of the system

we know that

The solution of the system of equations is the intersection point both graphs

The intersection point is (6,25) ----> see the graph

therefore

The ordered pair (6,25) is a solution to both $y=-\frac{5}{2}x+40$ and

$y=\frac{5}{3}x+15$

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3 years ago

30-60-90 Triangle Practice

ella [17]

Answer:

When there are numbers like that next to the radical it means multiply. like this: 2√9. You would first figure out the square root. Square root of 9 is 3. 2 times 3 is 6.

After you figure out those problems, you just need to put the number, x, and y in an equation with 2 unknowns.

Step-by-step explanation:

4 0

2 years ago

Read 2 more answers

State if the two triangles are congruent. if they are state how you know.

nlexa [21]

1) The triangles are congruent by SSS.

The two tick marks indicate two pairs of congruent sides; it is evident that the third side is congruent by the way the diagram is drawn - the bases of the triangles are together and appear to be the same length.

2) The triangles are congruent by SAS.

The two pairs of tick marks indicate congruent sides, and their included angles are congruent because they are vertical angles, and vertical angles are always congruent.

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3 years ago