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agasfer [191]
3 years ago
10

V=vi+at^2 dimensional correct

Physics
1 answer:
I am Lyosha [343]3 years ago
8 0

Answer:

Yes, dimensionally the equation is correct.

Explanation:

This equation is the kinematic equation for uniformly accelerated motion, then we study the units of each member to conclude whether it is dimensionally correct.

vi = initial velocity [m/s]

a = acceleration [m/s^2]

t = time [s]

v = final velocity

therefore we have:

[m/s] + [m/s^2]*[t^2], the second term now is m/s

[m/s]  + [m/s] = [m/s]

So the analysis is correct.

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A 200g air-track glider is attached to a spring. The glider is pushed in 10cm and released. A student with a stopwatch finds tha
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The spring constant will be k= 5.5N/m for a 200g air track glider attached to a spring.

<h3>What is spring constant?</h3>

The spring constant, k, is a measure of the stiffness of the spring. It is different for different springs and materials.

Calculation for What is the spring constant

First step is to calculate the time period

T = 12 second/10

T = 1.2 second

Now let calculate the spring constant using this formula

k=\dfrac{4\pi ^2m}{T^2}

Where,

m=0.2kg

T=1.2second

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Let plug in the formula

k=\dfrac{4 \pi \times 0.2}{(1.2)^2}

k=\dfrac{39.48\times 0.2}{1.44}

k=\dfrac{7.90}{1.44}

k=5.48 N/m

k=5.5 N/m ( Approximately)

Therefore the spring constant will be 5.5 N/m

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4 0
2 years ago
An electron and a proton are held on an x axis, with the electron at x = + 1.000 m and the proton at x = - 1.000 m. Part A How m
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PART A)

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3 years ago
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Answer:

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<h2>What is a Database table?</h2>

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