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3 years ago

9

X²-5÷x-2quiero la respuesta

1 answer:

Mashutka [201]3 years ago

6 0

Evaluate the power,subtract the numbers then write all the numerator above the common denominator.

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Explain how you know that 7/12 is greater than 1/3 but less t than 2/3

Dmitrij [34]

You would make all the fractions have the same common denominator of 12. First you would keep the fraction 7/12 because the denominator is already 12. Next you would take the fraction 1/3 and multiply it by 4/4 and the new fraction for 1/3 becomes 4/12. Lastly you would take 2/3 and multiply that by 4/4 and the fraction becomes 8/12. Now you can compare the fractions with the same denominator. Therefore 7/12 is greater than 1/3 but less than 2/3

8 0

3 years ago

5a-3b+c+(4-5b-c) ayuda

JulsSmile [24]

La respuesta es 5a - 8b + 4

5 0

3 years ago

Rewrite without absolute value sign for different values of x: y=− 2x+5 + 2x−5 if x<−2.5; if x>2.5; if −2.5≤x≤2.5

valentina_108 [34]

Answer:

x<-2.5 =(2x+5)-(2x-5) 2. 5-5

3.0

Step-by-step explanation:

PLz make brainlestiset answer

4 0

3 years ago

A string passing over a smooth pulley carries a stone at one end. While its other end is attached to a vibrating tuning fork and

nasty-shy [4]

Answer:

correct option is C) 2.8

Step-by-step explanation:

given data

string vibrates form = 8 loops

in water loop formed = 10 loops

solution

we consider mass of stone = m

string length = l

frequency of tuning = f

volume = v

density of stone = $\rho$

case (1)

when 8 loop form with 2 adjacent node is $\frac{\lambda }{2}$

so here

$l = \frac{8 \lambda _1}{2}$ ..............1

$l = 4 \lambda_1\\\\\lambda_1 = \frac{l}{4}$

and we know velocity is express as

velocity = frequency × wavelength .....................2

$\sqrt{\frac{Tension}{mass\ per\ unit \length }}$ = f × $\lambda_1$

here tension = mg

so

$\sqrt{\frac{mg}{\mu}}$ = f × $\lambda_1$ ..........................3

and

case (2)

when 8 loop form with 2 adjacent node is $\frac{\lambda }{2}$

$l = \frac{10 \lambda _1}{2}$ ..............4

$l = 5 \lambda_1\\\\\lambda_1 = \frac{l}{5}$

when block is immersed

equilibrium eq will be

Tenion + force of buoyancy = mg

T + v × $\rho$ × g = mg

and

T = v × $\rho$ - v × $\rho$ × g

from equation 2

f × $\lambda_2$ = f × $\frac{1}{5}$

$\sqrt{\frac{v\rho _{stone} g - v\rho _{water} g}{\mu}} = f \times \frac{1}{5}$ .......................5

now we divide eq 5 by the eq 3

$\sqrt{\frac{vg (\rho _{stone} - \rho _{water})}{\mu vg \times \rho _{stone}}} = \frac{fl}{5} \times \frac{4}{fl}$

solve irt we get

$1 - \frac{\rho _{stone}}{\rho _{water}} = \frac{16}{25}$

so

relative density $\frac{\rho _{stone}}{\rho _{water}} = \frac{25}{9}$

relative density = 2.78 ≈ 2.8

so correct option is C) 2.8

3 0

3 years ago

PLEASE HELP FAST!!!!<br><br> Fill in the blanks <br><br> Solve using the elimination method

Rainbow [258]

Answer: Look below

Step-by-step explanation:

1(10x-6y)=-16

3(5x+2y)=66

10x-6y=-16

15x+6y=66

-25x=50

x=-2

6 0

3 years ago