0.0036g of NH4+ x 1mol of NH4+/18.04g of NH4+ x 6.02*10^23 electrons of NH4+/1mol of NH4+
= 1.20 x 10^20 electrons of NH4+
<h3>Answer:</h3>
Volume = 11.2 L
<h3>Explanation:</h3>
Step 1: Calculate Moles:
As we know one mole of any substance contains 6.022 × 10²³ particles (atoms, ions, molecules or formula units). This number is also called as Avogadro's Number.
The relation between Moles, Number of Particles and Avogadro's Number is given as,
Number of Moles = Number of Particles ÷ 6.022 × 10²³
Putting values,
Number of Moles = 3.01× 10²³ Particles ÷ 6.022 × 10²³
Number of Moles = 0.50 Moles
Step 2: Calculate Volume:
As we know that one mole of any Ideal gas at standard temperature and pressure occupies exactly 22.4 dm³ volume.
When 1 mole gas occupies 22.4 dm³ at STP then the volume occupied by 0.50 moles of gas is calculated as,
= (22.4 dm³ × 0.50 moles) ÷ 1 mole
= 11.2 dm³ ∴ 1dm³ = 1 L
So,
Volume = 11.2 L
Answer:
Son aquellas en las que hay más de un verbo núcleo de predicado, por lo que dos o más oraciones forman una más grande; por ejemplo: A Carlos le gusta el fútbol, pero a María solo le gusta el cricket.
Explanation:
