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oksano4ka [1.4K]
2 years ago
9

a researcher obtains a sample of 0.070 M nitrate solition. A 20.0 mL aliquote of the nitrate solution is added to 10.0 mL of amm

onia and diluted to 100 ml with deionized water. what is the concentration of nitrate in the new solution
Chemistry
1 answer:
katovenus [111]2 years ago
6 0

Answer:

Concentration of nitrate in the new solution = 0.007 M

Explanation:

Given:

Concentration nitrate solution = 0.070 m

Volume of aliquote of the nitrate solution is add = 10.0 ml

Total volume = 100 ml

Find:

Concentration of nitrate in the new solution

Computation:

Number of M. mole = 0.070 m x 10.0 ml

Number of M. mole = 0.7 m-moles

Concentration of nitrate in the new solution = 0.7 m-moles / 100 ml

Concentration of nitrate in the new solution = 0.007 M

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Answer:

2.47x10^{25}atoms

Explanation:

Hello,

In this case, since the mineral torbernite has one copper atom, two uranium atoms, twenty oxygen atoms (2x2+4x2+8), two phosphorous atoms and sixteen hydrogen atoms (12x2) and therefore forty one in total, by using the Avogadro's number one is able to compute the total number of atoms in one formula unit or one mole:

Atoms=1molCu(UO_2)_2(PO_4)_2\dot \ 8H_2O*\frac{41mol\ of \ atoms}{1molCu(UO_2)_2(PO_4)_2\dot \ 8H_2O}*\frac{6.022x10^{23}atoms}{1mol\ of \ atoms}  \\\\=2.47x10^{25}atoms

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2 years ago
Which property of physical changes explains why matter is conserved in a physical change
choli [55]

Answer:

hi im new because of its solid state

Explanation:

7 0
3 years ago
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Determine the partial pressure and number of moles of each gas in a 15.75-L vessel at 30.0 C containing a mixture of xenon and n
lawyer [7]

Answer:

The Partial pressure of Xe and Ne will be 4.95 atm and 1.55 atm. The number of moles of Xe and Ne will be 3.13 and 0.981

Explanation:

Let the total pressure of the vessel= 6.5 atm and mole fraction of Xenon= 0.761

As we know,

\chi_{Ne} + \chi_{Xe} = 1\\\chi_{Ne}= 1- 0.761\\\chi_{Ne}= 0.239

According to Dalton's Law of partial pressure-

P_i=\chi_i\times P_{total}

Where,

P_i=The pressure of the gas component in the mixture

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P_t= The total pressure of the mixture

P_{Xe}=(0.761)\times(6.5)\\P_{Xe}= 4.95 atm\\\\\\P_{Ne}=(0.239)\imes (6.5)\\P_{Ne}= 1.55 atm

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To calculate the number of moles,

PV=nRT

n=\frac{PV}{RT}

n_{Xe}= \frac{4.95\times 15.75}{0.0821\times303 }\\ n_{Xe}= \frac{77.96}{24.87} \\n_{Xe}= 3.13\,mole \\\\\\n_{Ne}= \frac{1.55\times 15.75}{0.0821\times303 }\\\\n_{Ne}=\frac{24.41}{24.87}\\ n_{Ne}=0.981 \,mole

Learn more about Dalton's Law of partial pressure here;

brainly.com/question/14119417

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1 year ago
Electron configuration of ag
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