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Gelneren [198K]
3 years ago
5

Use your answers from questions 1–3 as the basis for the first section of your lab report. This section provides your reader wit

h background information about why you conducted this experiment and how it was completed. Outline the steps of the procedure in full sentences. It also provides potential answers (your hypothesis/es) relative to what you expected the experiment to demonstrate. This section should be 1–3 paragraphs in length.
Physics
1 answer:
kodGreya [7K]3 years ago
4 0

Answer:

Do you have a picture for this one I need to see the question.

Explanation:

You might be interested in
3. The soccer kicker kicks a 2 kg football with a force of 68 N. How fast will the ball accelerate down the field?
Katen [24]

Answer:

\boxed {\boxed {\sf m= 2 \ kg , \\a= 34 \ m/s^2,  \\\F= 68 \ N}}

Explanation:

The formula for force is:

F=m*a

If we rearrange the formula to solve for a (acceleration), the formula becomes

\frac{F}{m} =a

The force is 68 Newtons. Let's convert the units to make the problem easier later on. 1 N is equal to 1 kg*m/s², so the force of 68 N is equal to 68 kg*m/s².

The mass is 2 kilograms.

F=68 \ kg*m/s^2 \\m= 2\ kg

Substitute the values into the formula.

\frac{68 \ kg*m/s^2}{2 \ kg} =a

Divide. Note that the kilograms will cancel each other out (hence why we changed the units).

\frac{68 \ m/s^2}{2}=a

34 \ m/s^2=a

The acceleration is<u> </u><u>34 meters per second squared.</u>

6 0
3 years ago
A force of 80 N is exerted on an object on a frictionless surface for a distance of 4 meters. If the object has a mass of 10 kg,
solmaris [256]
There are two ways to find energy. Energy=F*d=mv^2. We can use this relationship to find v:
Fd=0.5mv^{2} \\ 80*4=0.5*10v^{2} \\ 64=v^{2} \\ v=8 m/s
6 0
3 years ago
Suppose a plane accelerates from rest for 30 s, achieving a takeoff speed of 80 m/s after traveling a distance of 1200 m down th
Margaret [11]

Answer:

300 m

Explanation:

The train accelerate from the rest so u = 0 m/sec

Final speed that is v = 80 m/sec

Time t = 30 sec

The distance traveled by first plane = 1200 m

We know the equation of motion S=ut+\frac{1}{2}at^2 where s is distance a is acceleration and u is initial velocity

Using this equation for first plane 1200=0\times 30+\frac{1}{2}a30^2

a=2.67\frac{m}{sec^2}

As the acceleration is same for both the plane so a for second plane will be 2.67 \frac{m}{sec^2}

The another equation of motion is v^2=u^2+2as using this equation for second plane 40^2=0+2\times 2.67\times s

s = 300 m

5 0
2 years ago
When Bella pushes a box with a mass of 5.25 kilograms with a force of 15.75 newtons, it accelerates at a rate of 2.5 meters/seco
Mariana [72]

Sure !

Start with Newton's second law of motion:

                     Net Force = (mass) x (acceleration) .

This formula is so useful, and so easy, that you really
should memorize it.

Now, watch:

The mass of the box is 5.25 kilograms, and the box is
accelerating at the rate of  2.5 m/s² .
What's the net force on the box ?

                    Net Force = (mass) x (acceleration)

                                     = (5.25 kilograms) x (2.5 m/s²)

                     Net force =       13.125 newtons .

But hold up, hee haw, whoa !  Wait a second !
Bella is pushing with a force of 15.75 newtons, but the box
is accelerating as if the force on it is only 13.125 newtons.
What happened to the rest of Bella's force ? ?

==>  Friction is pushing the box in the opposite direction,
and cancelling some of Bella's force.

How much ?

            (Bella's 15.75 newtons) minus (13.125 that the box feels)

           =      2.625 newtons backwards, applied by friction.


5 0
3 years ago
Read 2 more answers
Light hits a mirror at a 45° angle. It will be reflected at an angle _____.
Eddi Din [679]
It will be equal to 45°
6 0
2 years ago
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