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3 years ago

A microspectrophotometer measures which of the following?

Chemistry

1 answer:

iragen [17]3 years ago

4 0

Answer : The correct option is, Light absorption

Explanation :

Microspectrophotometer : It is a type of instrument that measures the spectra of the microscopic sample by using the different wavelengths of an electromagnetic radiation.

It is designed to measure the the spectrum of the microscopic sample. It is also measure the transmittance, absorbance, polarization and fluorescence of the microscopic sample.

From the given options, the option light absorption is the correct option.

Hence, a microspectrophotometer measures the light absorption.

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Blackmail threat of informational disclosure is an example of which threat category?

Rashid [163]

Answer:

Information Extortion.

Explanation:

Computer oriented crime also known as cyber crime that intentionally harm the victims. The complete data of the company or net banking information can be hacked easily by the cyber crime.

Different category of the threats are included in the cyber crime. The information extortion threat is the crime in which the hackers hack complete information and control the data of the victim. The criminal an black mail the victim regarding the hacked data.

Thus, the correct answer is information extortion.

6 0

2 years ago

What is the percent composition by mass of oxygen in

KiRa [710]

What is the percent composition by mass of oxygen in magnesium oxide, MgO?

Answer: 39.7 percent

4 0

2 years ago

What is the full form of alcl3

Likurg_2 [28]

Answer:

Aluminum Chloride

Explanation:

8 0

3 years ago

A 17.11 gram sample of an organic compound containing only C, H, and O is analyzed by combustion analysis and 21.71 g CO2 and 5.

Andru [333]

Answer: The empirical formula and the molecular formula of the organic compound is $CHO$ and $C_4H_4O_4$ respectively.

Explanation:

The chemical equation for the combustion of hydrocarbon having carbon, hydrogen and oxygen follows:

$C_xH_yO_z+O_2\rightarrow CO_2+H_2O$

where, 'x', 'y' and 'z' are the subscripts of Carbon, hydrogen and oxygen respectively.

We are given:

Mass of $CO_2$ = 21.71 g

Mass of $H_2O$ = 5.926 g

Molar mass of carbon dioxide = 44 g/mol

Molar mass of water = 18 g/mol

For calculating the mass of carbon:

In 44g of carbon dioxide, 12 g of carbon is contained.

So, in 21.71 g of carbon dioxide, = $\frac{12}{44}\times 21.71=5.921g$ of carbon will be contained.

For calculating the mass of hydrogen:

In 18g of water, 2 g of hydrogen is contained.

So, in 5.926 g of water, = $\frac{2}{18}\times 5.926=0.658g$ of hydrogen will be contained.

Mass of oxygen in the compound = (17.11) - (5.921+0.658) = 10.53 g

Mass of C = 5.921 g

Mass of H = 0.658 g

Mass of O = 10.53 g

Step 1 : convert given masses into moles.

Moles of C = $\frac{\text{ given mass of C}}{\text{ molar mass of C}}= \frac{5.921g}{12g/mole}=0.493moles$

Moles of H= $\frac{\text{ given mass of H}}{\text{ molar mass of H}}= \frac{0.658g}{1g/mole}=0.658moles$

Mass of O= $\frac{\text{ given mass of O}}{\text{ molar mass of O}}= \frac{10.53g}{16g/mole}=0.658moles$

Step 2 : For the mole ratio, divide each value of moles by the smallest number of moles calculated.

For C = $\frac{0.493}{0.493}=1$

For H = $\frac{0.658}{0.493}=1$

For O= $\frac{0.658}{0.493}=1$

The ratio of C : H: O = 1: 1: 1

Hence the empirical formula is $CHO$ .

empirical mass of CHO = 12(1) + 1(1) + 1 (16) = 29

Molecular mass = 104.1 g/mol

$n=\frac{\text {Molecular mass}}{\text {Equivalent mass}}=\frac{104.1}{29}=4$

Thus molecular formula = $n\times {\text {Empirical formula}}=4\times CHO=C_4H_4O_4$

6 0

2 years ago

Calculate the mass in grams of a sample of Americium containing six atoms

elena-14-01-66 [18.8K]

Americium has a molar mass of 243 g/mol.
There are 6.022*10^23 atoms in a mol (Avogadro's number).

6 atoms / 6.022 * 10^23 atoms/mol gives us:

9.963*10^-24 mols

Lastly: 9.963*10^-24 mols * 243 g/mol = 2.42*10^-21 g

8 0

2 years ago

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