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Trava [24]
3 years ago
10

This was in my chemistry class- What's the color combination code?

Chemistry
1 answer:
Aleksandr-060686 [28]3 years ago
3 0
Blue yellow purple green
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Predict whether litmus paper will turn red or blue when dipped in:
Temka [501]

Answer:

a. blue, b. red, c. red, d. basic - blue

Explanation:

a.washing powder ( containing sodium carbonate ) basic -blue

b. orange juice ( containing citric acid )- acidic -red

c. lemonade ( containing H2CO₃ )-acidic - red

d. cleaner ( containg NH₃ )- basic - blue

7 0
3 years ago
NaOH is typically standardized using potassium hydrogen phthalate (KHP).
DaniilM [7]

Answer:

Na(OH)²

Explanation:

We look for the charges in the periodic table

6 0
3 years ago
A 0.539 g sample of a metal, M, reacts completely with sulfuric acid according to the reaction M(s)+H2SO4(aq)⟶MSO4(aq)+H2(g) A v
Charra [1.4K]

Answer:

The molar mass of the metal is 54.9 g/mol.

Explanation:

When we work with gases collected over water, the total pressure (atmospheric pressure) is equal to the sum of the vapor pressure of water and the pressure of the gas.

Patm = Pwater + PH₂

PH₂ = Patm - Pwater = 1.0079 bar - 0.03167 bar = 0.9762 bar

The pressure of H₂ is:

0.9762bar.\frac{1atm}{1.013bar} =0.9637atm

The absolute temperature is:

K = °C + 273 = 25°C + 273 = 298 K

We can calculate the moles of H₂ using the ideal gas equation.

P.V=n.R.T\\n=\frac{P.V}{R.T} =\frac{0.9637atm \times 0.249L }{(0.08206atm.L/mol.K)\times298K} =9.81 \times 10^{-3} mol

Let's consider the following balanced equation.

M(s) + H₂SO₄(aq) ⟶ MSO₄(aq) + H₂(g)

The molar ratio of M:H₂ is 1:1. So, 9.81  × 10⁻³ moles of M reacted. The molar mass of the metal is:

\frac{0.539g}{9.81 \times 10^{-3} mol} =54.9g/mol

4 0
4 years ago
Write the Noble Gas Notation for Silicone
ozzi

Answer:

[Ne] 3s2 3p2

Explanation:

Neon (Ne) is the noble gas right before silicon (Si).

Then right after neon is the 3s subshell. It has two electrons and is full.

After 3s comes the 3p subshell, and silicon only has two electrons in the 3p subshell (you can just count the electrons in each subshell on your periodic table).

8 0
3 years ago
650. J is the same amount of energy as A. 155 cal. B. 2720 calC. 650 cal.D. 1550 cal.
sladkih [1.3K]

Answer:

A\text{ : 155 cal}

Explanation:

Here, we want to convert J to cal

Mathematically:

1\text{ cal = 4.186 J}

Thus, to get our answer in cal, we divide the value given by 4.186

We have that as:

\frac{650}{4.186}\text{ = 155 cal}

5 0
1 year ago
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