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3 years ago

How can two objects of different masses have the same temperature but different amounts of thermal energy?

Chemistry

1 answer:

galben [10]3 years ago

4 0

The masses can affect the thermal energy even if it’s the same temperature

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What do the images embedded in rock represent?

xeze [42]

You're correct It's D :))))))))<span />

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3 years ago

Consider the decomposition of hydrogen peroxide reaction. If the rate of decomposition of hydrogen peroxide at a particular temp

Natasha2012 [34]

Answer:

0.049 mol/L.s

Explanation:

The decomposition of hydrogen peroxide is:

$H_2O_2 \to H_2O + \dfrac{1}{2}O_2$

$Rate = -\dfrac{\Delta [H_2O_2]}{\Delta t}= \dfrac{\Delta [H_2O_2]}{\Delta t}= \dfrac{ 2 \Delta [H_2O_2]}{\Delta t}$

The rate of decomposition reaction = the rate of formation of $H_2O$ = 0.098 mol/L.s

∴

Rate of formation of $O_2$ $= \dfrac{ rate \ of \ reaction }{2}$

$= \dfrac{ 0.098 }{2}$

= 0.049 mol/L.s

8 0

3 years ago

Calculate the mass % of K in potassium phosphate

Blizzard [7]

Answer:

$\large \boxed{\mathbf{1. \, \,55.26 \, \%; \, \,2. \, \,30.15 \, \% }}$

Explanation:

1. Mass percent of K

$\begin{array}{cccr}\mathbf{Atoms} & \textbf{Contribution} & & \textbf{Subtotal}\\\text{3K} & 3 \times 39.10 & = & 117.30\\\text{1P} & 1 \times 30.97 & = & 30.97\\\text{4O} & 4 \times 16.00 & = &64.00\\& \text{TOTAL} & = & \mathbf{212.27}\\\end{array}$

$\text{Percent K} = \dfrac{\text{117.30 g}}{\text{212.27 g}} \times \, 100\% = \mathbf{55.26 \, \%}\\\text{The percent by mass of potassium is $\large \boxed{\mathbf{55.26 \, \% }}$}$

2. Mass percent of O

$\text{Percent O} = \dfrac{\text{64.00 g}}{\text{212.27 g}} \times \, 100\% = \mathbf{30.15 \, \%}\\\text{The percent by mass of oxygen is $\large \boxed{\mathbf{30.15 \, \% }}$}$

6 0

3 years ago

Planck's constant, h, is 6.626 x 10-34 Js. The speed of light in a vacuum, c, is 3.00 x 108 m/s. Calculate the energy of ultravi

igomit [66]

Given the Planck's constant and the speed of light, the energy of the ultraviolet light with a frequency of 9.58×10¹⁴ Hz is 6.35×10¯¹⁹ J (Option C)

<h3>Data obtained from the question </h3>

Planck's constant (h) = 6.626×10¯³⁴ Js
Speed of light (v) = 3×10⁸ m/s
Frequency (f) = 9.58×10¹⁴ Hz
Energy (E) =?

<h3>How to determine the energy </h3>

The energy of the ultraviolet light can be obtained as follow:

E = hf

E = 6.626×10¯³⁴ × 9.58×10¹⁴

E = 6.35×10¯¹⁹ J

Learn more about energy:

brainly.com/question/10703928

8 0

2 years ago

The proper name for PCl6 is phosphorus hexachloride.<br><br> TRUE<br><br> FALSE

Alenkasestr [34]

The proper name for PCI6 is phosphorus hexachloride. Therefore it’s true

8 0

2 years ago

How can two objects of different masses have the same temperature but different amounts of thermal energy?​

How can two objects of different masses have the same temperature but different amounts of thermal energy?