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Daniel [21]
3 years ago
5

An engine that has an efficiency of 25% takes in 200 [J] of heat during each cycle. Calculate the amount of work this engine per

forms.
Physics
1 answer:
BartSMP [9]3 years ago
5 0

Answer:

W=50J

Explanation:

The work done W and the energy taken Q_{in} by a heat engine are related to the efficiency \eta by the expression

\eta=\frac{W}{Q_{in}}

The efficiency is \eta=25%, the numerical form of this percentage is 0.25 and the energy taken is Q_{in}=200J. Replacing in the formula:

0.25=\frac{W}{200}\\W=200*0.25\\W=50J

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A 1.50 kg rock is thrown up into the air from ground level, reaches a maximum height of 7.00 m, then returns to the ground. Calc
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Answer:

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Momentum = mass × velocity

I = mv..................... Equation 1

But we can calculate the value of v  using the equation of motion under gravity.

v² =  u²+2gs............. Equation 2

Where u = initial velocity, s = maximum heigth, g = acceleration due to gravity.

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3 0
2 years ago
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Explanation:

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Centripetal force is given by;

F_c = \frac{mv^2}{r}\\\\

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Therefore, the linear velocity of the object is 8.71 m/s.

4 0
3 years ago
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