Question

An engine that has an efficiency of 25% takes in 200 [J] of heat during each cycle. Calculate the amount of work this engine performs.

Answer 1

Answer:

$W=50J$

Explanation:

The work done $W$ and the energy taken $Q_{in}$ by a heat engine are related to the efficiency $\eta$ by the expression

$\eta=\frac{W}{Q_{in}}$

The efficiency is $\eta$=25%, the numerical form of this percentage is 0.25 and the energy taken is $Q_{in}$=200J. Replacing in the formula:

$0.25=\frac{W}{200}\\W=200*0.25\\W=50J$