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3 years ago

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2.1 Define Resultant vector

1 answer:

lord [1]3 years ago

3 0

Explanation:

In vector geometry, the resultant vector is defined as: “A resultant vector is a combination or, in simpler words, can be defined as the sum of two or more vectors which has its own magnitude and direction.”

I hope it's helpful!

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015 10.0 points

Salsk061 [2.6K]

Answer:

20.996 m

Explanation:

Given:

Initial velocity, $u=0 \textrm{ m/s}$

Final velocity, $v=12.4062 \textrm{ m/s}$

Total time taken, $t_{Total} = 7.13$ s.

∴ Acceleration is given as,

$a=\frac{v-u}{t_{Total}}=\frac{12.4062-0}{7.13}=1.74$ m/s²

Now, using Newton's equation of motion, we find the displacement.

Displacement is given as:

$s=ut+\frac{1}{2} at^{2}$

Plug in 0 for $u$ , 4.91257 for $t$ and 1.74 for $a$ . Solve for $s$ .

This gives,

$s=0+\frac{1}{2} \times 1.74 \times (4.91257)^{2}=20.996 \textrm{ m}$

Therefore, the train's displacement in the first 4.91257 s of motion is 20.996 m.

7 0

3 years ago

suppose larry stands with more weight on one scale than the other if one scale reads 400 N. what does the other read?

Evgen [1.6K]

The other scale will either have a higher or lower number because 400 could be the bigger number or the smaller number but we don't know that so you cant exactly answer it.<span />

8 0

3 years ago

Read 2 more answers

Using the superposition method, calculate the current through R5 in Figure 8-71

Natasha2012 [34]

by superposition method we can find current in R5

here first let say only 2V battery is present in the circuit

now the equivalent resistance to be found for which we can say

2.2 k ohm and 1 k ohm is connected in parallel

$r_1 = \frac{2.2 * 1}{2.2 + 1}$

$r_1 = 0.6875 k ohm$

now it is in series with 1 k ohm and then that part is in parallel with 2.2 k ohm

$r_2 = \frac{2.2* (1+0.6875)}{2.2 + (1+0.6875)}$

$r_2 = 0.95 k ohm$

now the current flowing through the battery is

$i = \frac{2}{1 + 0.95} = 1.02 mA$

now this will divide into R3 and R2 so current flowing in R3 will be

$i_1 = \frac{2.2}{2.2+1.6875}*1.02 = 0.58 mA$

now this will again divide in R4 and R5

so current in R5 will be

$i_5 = \frac{R_4}{R_4 + R_5}* i_1$

$i_5 = 0.18 mA$

now when only 3 V battery is present in the circuit

R1 and R2 is in parallel and then it is in series with R3

so parallel combination will be

$r_1 = \frac{1*2.2}{2.2 +1} = 0.6875k ohm$

also after its series with R3

$r_2 = 1 + 0.6875 = 1.6875 k ohm$

now it is in parallel with R5 on other side

$r_3 = \frac{1.6875 * 2.2}{1.6875 + 2.2} = 0.95 k ohm$

now current through the battery will be given as

$i = \frac{3}{1 + 0.95} = 1.53 mA$

now it is divide in r2 and R5

so current in R5 is given as

$i_5 = \frac{r_2}{r_2 + R_5}*i$

$i_5 = \frac{1.6875}{2.2 + 1.6875} * 1.53$

$i_5 = 0.67 mA$

now the total current in R5 will be given by super position which is

$i = 0.67 + 0.18 = 0.85 mA$

so there is 0.85 mA current through R5 resistance

8 0

3 years ago

You are given a copper bar of dimensions 3 cm × 5 cm × 8 cm and asked to attach leads to it in order to make a resistor. If you

max2010maxim [7]

Answer:

$c. 5cm \times 8cm$

Explanation:

The dimensions $5cm\times 8cm$ have the highest cross-sectional area combination of $40cm^2$ .

-Resistance reduces with an increase in cross sectional area.

- $Reason-$ Electrons have alarger area to flow through.

8 0

4 years ago

A ball of mass 0.12kg is hit by a tennis player.

Alik [6]

Answer:

blah blah blahblah

Explanation:

because math is math and nobody understands it

3 0

3 years ago