Impulse is the change in momentum. So you just have to subtract 300 -280
The answer would be 20kgm/s
Answer:
y = 54.9 m
Explanation:
For this exercise we can use the relationship between the work of the friction force and mechanical energy.
Let's look for work
W = -fr d
The negative sign is because Lafourcade rubs always opposes the movement
On the inclined part, of Newton's second law
Y Axis
N - W cos θ = 0
The equation for the force of friction is
fr = μ N
fr = μ mg cos θ
We replace at work
W = - μ m g cos θ d
Mechanical energy in the lower part of the embankment
Em₀ = K = ½ m v²
The mechanical energy in the highest part, where it stopped
= U = m g y
W = ΔEm = - Em₀
- μ m g d cos θ = m g y - ½ m v²
Distance d and height (y) are related by trigonometry
sin θ = y / d
y = d sin θ
- μ m g d cos θ = m g d sin θ - ½ m v²
We calculate the distance traveled
d (g syn θ + μ g cos θ) = ½ v²
d = v²/2 g (sintea + myy cos tee)
d = 9.8 12.6 2/2 9.8 (sin16 + 0.128 cos 16)
d = 1555.85 /7.8145
d = 199.1 m
Let's use trigonometry to find the height
sin 16 = y / d
y = d sin 16
y = 199.1 sin 16
y = 54.9 m
Answer:
1/9 E0
Explanation:
The computation is shown below:
As we know that
where,
E = Electric field strength
k = Coulomb's constant
Q = charge on the sphere
r = distance from the center of the sphere
It is given that
The radius of the larger sphere is three times larger than that of the smaller sphere i.e
hence, the last option is correct
The historical method includes what steps?
Answer:
More-massive gas molecules in the sample have lower rms speed than less-massive ones.
Explanation:
The rms speed is defined as the prediction that how fast the molecule travel at a given temperature.
Mathematically, rms speed can be written as,
Here, T is the temperature, M is the mass of gas molecule.
Now from this it is clearly seen that rms speed is inversely related with mass of the gas molecule.
Therefore, gas molecule which posses more mass in the sample have smaller rms speed than less-massive ones.