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Katen [24]
4 years ago
9

You measure the power delivered by a battery to be 4.26 W when it is connected in series with two equal resistors. How much powe

r will the same battery deliver if the resistors are now connected in parallel across it
Physics
1 answer:
gtnhenbr [62]4 years ago
3 0

Answer:

<em>The power delivered by the battery is 17.04 W</em>

Explanation:

Power through a circuit is given as

P = IV    ....1

where P is the power

I is the current through the circuit

V is the voltage through the circuit

The voltage in a circuit is given as

V = IR    ....2

Let us take the value of each resistor as equal to R

when connected in series, the total resistance will be

R_{t} = R + R = 2R

If we assume constant voltage through the circuit, then from equation 2, the current in this case is

I = V/2R

If the resistors are connected in parallel, then the total resistance will be

\frac{1}{R_{t} } = \frac{1}{R} +

R_{t} = R/2

The current in this case will be increased since the resistance is reduced

I = 2V/R

comparing the two situations, we can see that the current increased when connected in parallel to a ratio of

\frac{2V}{R} ÷  \frac{V}{2R} =  

This means that the current increased 4 times

From equation 1, we can see that electrical power is proportional to the current at a constant voltage, therefore, the power will also increase by four times to

P = 4 x 4.26 = <em>17.04 W</em>

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It means that if you had a cubic meter of water it would weigh 1000 kilograms
4 0
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What force is needed to propel a 421-kg car with an acceleration of 3.77 m/s2?
nekit [7.7K]

brainly.com/question/11542618?answering=true&answeringSource=greatJob%2FquestionPage

7 0
3 years ago
An object is 15 cm in front of a diverging lens with a
Rainbow [258]

A) See ray diagram in attachment (-6.0 cm)

By looking at the ray diagram, we see that the image is located approximately at a distance of 6-7 cm from the lens. This can be confirmed by using the lens equation:

\frac{1}{q}=\frac{1}{f}-\frac{1}{p}

where

q is the distance of the image from the lens

f = -10 cm is the focal length (negative for a diverging lens)

p = 15 cm is the distance of the object from the lens

Solving for q,

\frac{1}{q}=\frac{1}{-10 cm}-\frac{1}{15 cm}=-0.167 cm^{-1}

q=\frac{1}{-0.167 cm^{-1}}=-6.0 cm

B) The image is upright

As we see from the ray diagram, the image is upright. This is also confirmed by the magnification equation:

h_i = - h_o \frac{q}{p}

where h_i, h_o are the size of the image and of the object, respectively.

Since q < 0 and p > o, we have that h_i >0, which means that the image is upright.

C) The image is virtual

As we see from the ray diagram, the image is on the same side of the object with respect to the lens: so, it is virtual.

This is also confirmed by the sign of q in the lens equation: since q < 0, it means that the image is virtual

4 0
3 years ago
A lead nucleus is spherical with a radius of about 7 ✕ 10⁻¹⁵ m. The nucleus contains 82 protons (and typically 126 neutrons). Be
Komok [63]

Answer:

∈=3.1584x10^{26} \frac{V}{m}

Explanation:

Using the Gauss Law to determine the electric field of the net flux at the surface of the nucleus

∈=\frac{P}{E_{o}}

The P is the charge density and 'Eo' is the constant of permittivity in free space

to find P

P=\frac{q}{V}

V=\frac{4}{3}*\pi*r^3

V=\frac{4}{3}\pi*(7x10^{-15})^3

V=2.932x10^{-14} m^3

P=\frac{82C}{2.932x10^{-14}m^3}=2.7965x10^{15} \frac{C}{m^3}

So replacing

∈=\frac{2.7965x10^{15}\frac{C}{m^3}}{8.8542x10^{-12}\frac{C^2}{N*m^2}}

∈=3.1584x10^{26} \frac{V}{m}

3 0
4 years ago
1.
drek231 [11]

Answer:

2500m

Explanation:

given,

initial velocity(u) = 5m/s

final velocity (v) = 0 m/s ( as he/she stopped riding after 1000 secs)

time = 1000 secs

distance(s)=?

now,

s=( u+v ) ×t /2

=(5+0)×1000/2

=2500 m

hence, he /she travels 2500m far

8 0
3 years ago
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