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SVETLANKA909090 [29]
3 years ago
15

Write an explicit formula for an, the nth term of the sequence 11,2,-7

Mathematics
1 answer:
abruzzese [7]3 years ago
8 0

Answer:

a_{n} = 20 - 9n

Step-by-step explanation:

There is a common difference d between consecutive terms, that is

d = 2 - 11 = - 7 - 2 = - 9

This indicates the sequence is arithmetic with nth term

a_{n} = a₁ + (n - 1)d

where a₁ is the first term and d the common difference

Here a₁ = 11 and d = - 9 , then

a_{n} = 11 - 9(n - 1) = 11 - 9n + 9 = 20 - 9n

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Can somebody help me with my Geometry?​
bezimeni [28]

Answer:

∠KJL = 45°

∠x=45°

∠DBC=67.47°

Step-by-step explanation:

x+x=90

2x=90

x=45°

6 0
3 years ago
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Quick help: Explain how to solve the following system of equations. What is the solution to the system?
romanna [79]
-3x - 4y - 2z = 0
x + 3y + 2z = 1

-2x - y = 1

-4x - 4y - 2z = 10
3x + 4y +2z= 0

-x = 10. x = -10

-2(-10) - y = 1
20 - y = 1
-y = -19
y = 19

-10 + 3(19) + 2z = 1
-10 + 57 + 2z = 1
47 + 2z = 1
2z = -46
z= -23

check: 2(-10)+2(19)-23=-5
-20+38-23=-5
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7 0
4 years ago
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6x - 2y = 5
laiz [17]

Answer:

The given system has NO SOLUTION.

Step-by-step explanation:

Here, the given system of equation is:

6 x -  2 y = 5     .......... (1)

3 x  - y = 10          .... (2)

Multiply equation 2 with (-2), we get:

3 x  - y = 10     ( x -2)

⇒  - 6 x + 2 y = - 20

Now, ADD this to equation (1) , we get:

6 x - 2 y  - 6 x + 2 y  = 5 - 20

or, 0 = - 15

WHICH IS NOT POSSIBLE as 0 ≠ -15

Hence, the given system has NO SOLUTION.

7 0
3 years ago
The diameter of a circle is 6.8 m. Find the circumference to the nearest tenth<br>​
matrenka [14]

Answer:

21.4m

Step-by-step explanation:

Circumference : x diameter

is approximately 3.142

3.142 x 6.8 = 21.3656

Nearest tenth = 21.4m

5 0
2 years ago
Please help ASAP!
Kruka [31]

First, recall that

\sin(-\theta)=-\sin\theta

So if \sin(-\theta)=\dfrac15, then \sin\theta=-\dfrac15.

Second,

\tan\theta=\dfrac{\sin\theta}{\cos\theta}

We know that \tan\theta>0 and \sin\theta, which means we should also have \cos\theta.

Third,

\sin^2\theta+\cos^2\theta=1\implies\cos\theta=\pm\sqrt{1-\sin^2\theta}

but as we've already shown, we need to have \cos\theta, so we pick the negative root.

Finally,

\tan\theta=\dfrac{\sin\theta}{\cos\theta}\iff\dfrac6{\sqrt{12}}=\dfrac{-\frac15}{\cos\theta}\implies\cos\theta=-\dfrac1{5\sqrt3}

Unfortunately, none of the given answers match, so perhaps I've misunderstood one of the given conditions... In any case, this answer should tell you everything you need to know to find the right solution from the given options.

6 0
4 years ago
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