Answer:
The particle's velocity is 212.15 m/s.
Explanation:
Given that,
Charge of particle,
The magnitude of electric field, E = 1270 N/C
The magnitude of magnetic field, B = 1.28 T
Net force,
We need to find the magnitude of the particle's velocity. the net force acting on the particle is given by Lorentz force as :
So, the particle's velocity is 212.15 m/s.
Answer:
0.426 volts
Explanation:
It is given that,
The radius of a circular loop, r = 11.2 cm = 0.112 m
An elastic conducting material is stretched into a circular loop.
It is placed with its plane perpendicular to a uniform 0.880 T magnetic field.
The radius of the loop starts to shrink at an instantaneous rate of 68.8 cm/s, dr/dt = 0.688 m/s
We need to find the emf induced in the loop at that instant.
So, the magnitude of induced emf is 0.426 volts.
Answer:
m
Explanation:
At 10am, the minute hand and hour hand are ' 2 hours apart', since the minute hand is at 12pm and hour hand is at 10am.
Angle between the two hands = 2/12 * 360
= 60°
Arc Length =
=