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Greeley [361]
3 years ago
8

What is the MOST important factor in the changing of the seasons?

Chemistry
1 answer:
slava [35]3 years ago
6 0

Answer:

A. the earth’s tilt toward the sun

Explanation:

The most important factor in the changing of the seasons on the earth is the earth's tilt towards the sun.

This causes the differences in the amount of insolation which is incident on the earth surface. Throughout the year, as the earth continues to spin, it receives different amount of solar radiation all year round.

The sun is always overhead around the equator. Such regions of the world receives direct insolation and are mostly constrained to a wet and dry season.

Areas above the equator have the sun at an angle. The diffused sunlight present distinct seasons all year round.

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1) All matter is made of atoms. 2) Atoms are indivisible and indestructible.

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3 years ago
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A piece of brass is found to have a mass of 24.32 g. When placed in a graduated cyclinder with an initial reading of 5.60 mL the
Jobisdone [24]

Answer:

\rho=3.1g/mL

Explanation:

Hello,

In this case, considering that the density of a body is computed given its mass and volume:

\rho =\frac{m}{V}

Taking into account that the mass is 24.32 g and the volume is computed via the difference between the volume of the water with the brass and the volume of water by itself as follows:

V=13.50mL-5.60mL=7.9mL

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4 0
3 years ago
An artifact originally had 16 grams of​ carbon-14 present. the decay model upper a equals 16 e superscript negative 0.000121 ta=
xeze [42]

<u>Given:</u>

Initial amount of carbon, A₀ = 16 g

Decay model = 16exp(-0.000121t)

t = 90769076 years

<u>To determine:</u>

the amount of C-14 after 90769076 years

<u>Explanation:</u>

The radioactive decay model can be expressed as:

A = A₀exp(-kt)

where A = concentration of the radioactive species after time t

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k = decay constant

Based on the given data :

A = 16 * exp(-0.000121*90769076) = 16(0) = 0

Ans: Based on the decay model there will be no C-14 left after 90769076 years

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4 years ago
After undergoing alpha decay, an atom of radium-226 becomes
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The answer is b. radon-222. The alpha decay means that it will emit an alpha particle when decays. The alpha particle has two protons and two neutrons. So Radium(88) minus two protons will become Radon(86). And the atomic mass will become 226-4=222.
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3 years ago
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