Answer:
Separation by density
Explanation:
Mixtures are made up of two or more pure substances which tends to keep their individual identities. These components can be separated from each other by different physical techniques.
Mixtures are further classified as;
(i) Homogenous Mixture:
In this type of the mixtures the components are uniformly mixed and their properties as well as composition as uniform throughout. Such mixtures are also called as solutions.
The physical methods used to separate these components from each other are distillation (taking heat and pressure into account), Solvent extraction, Magnetic separation, Chromatography e.t.c.
(ii) Homogenous Mixture:
In this type of the mixtures the components are not uniformly mixed and their physical properties and composition are also not uniform.
The physical methods used to separate these components from each other are Filtration, Magnetic Separation, Centrifugation, Flotation e.t.c.
So, in given options the density can play role by settling the massive components of heterogenous mixture to sit at the bottom and separated
Answer:
The solution will not form a precipitate.
Explanation:
The Ksp of PbI₂ is:
PbI₂(s) ⇄ 2I⁻(aq) + Pb²⁺(aq)
Ksp = 1.40x10⁻⁸ = [I⁻]²[Pb²⁺] <em>Concentrations in equilibrium</em>
When 328mL of 0.00345M NaI(aq) is combined with 703mL of 0.00802M Pb(NO₃)₂. Molar concentration of I⁻ and Pb²⁺ are:
[I⁻] = 0.00345M × (328mL / (328mL+703mL) =<em> 1.098x10⁻³M</em>
[Pb²⁺] = 0.00802M × (703mL / (328mL+703mL) =<em> 5.469x10⁻³M</em>
<em />
Q = [I⁻]²[Pb²⁺] <em>Concentrations not necessary in equilibrium</em>
If Q = Ksp, the solution is saturated, Q > Ksp, the solution will form a precipitate, if Q < Ksp, the solution is not saturated.
Replacing:
Q = [1.098x10⁻³M]²[5.469x10⁻³M] = 6.59x10⁻⁹
As Q < Ksp, the solution is not saturated and <em>will not form a precipitate</em>.
Answer:
If the volume of a container is decreased, the temperature decreases, which means that the volume of a gas is directly proportional to its temperature
Answer:
Please find the solution in the attached file.
Explanation: