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dimaraw [331]
3 years ago
5

Does his mass change when he goes from Earth to its moon?

Physics
1 answer:
Aleonysh [2.5K]3 years ago
8 0

Answer:

The object's mass remains same in every place but its weight will change due to different gravity in both Earth and moon.

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enyata [817]

Answer:

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Explanation:

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5 0
3 years ago
A center-seeking force related to acceleration is _______ force.
zvonat [6]
<span>The question is 'a centre seeking force related to acceleration is ............... force. The answer is centripetal force. Motion in a curved path is an accelerated motion and it requires a force that will direct the moving object towards the centre of curvature of the path of motion. This centre seeking force is known as centripetal force.</span>
5 0
4 years ago
A heavy steel cable attached to a motor is lifting a girder. The girder is speeding up.
Yanka [14]

Answer: part a) both the tension and gravity vectors will be pointing downwards.

part b) the tension vector will be pointing upwards and the gravity will be pointing downwards.

Explanation:

part a) Since you are looking at the FBD for the steel cable here, the tension will be pointing downwards because the girder is hung from the cable which creates a downwards tension. Gravity will always point downwards, to the ground.

part b) Since you are looking at the FBD for the girder here, the tension will be pulled upwards because the cable is weighted which creates an upwards tension. Gravity will always point downwards, to the ground.

Sorry for the poor explanation, but hopefully this makes sense.

8 0
3 years ago
In the Fresnel circular aperture setup, the distances from the aperture to the light source and the reception screen are 1.5 m a
ivanzaharov [21]

Explanation:

The width of the central maximum is given by

W = 2 λ L / a

where W is the width of the central maximum

λ is the wavelength of the light used.

L is the distance between the aperture and screen

a is the width of the slit or aperture

So we can see that if any one quantity is varied by keeping others constant in the above formula , there would be a change in width of central maximum.

5 0
3 years ago
A 0.0450-kg golf ball initially at rest is given a speed of 25.2 m/s when a club strikes. part a part complete if the club and b
Ksenya-84 [330]
We are given information:
m = 0.0450 kg
Δv = 25.2 m/s
Δt = 1.95 ms = 0.00195s

To find force we use formula:
F = m * a

a is acceleration. To find it we use formula:
a = Δv / Δt 
a = 25.2 / 0.00195
a = 12923.1 m/s^2

Now we can find force:
F = 0.0450 * 12923.1
F = 581.5 N 


To check the effect of the ball's weight on this movement we need to calculate it and then compare it to this force.
W = m * g
W = 0.0450 * 9.81
W = 0.44145 N 

We can see that weight is much smaller than the applied force so it's influence in negligible.
3 0
3 years ago
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