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denis-greek [22]
2 years ago
12

Is kcl and kvl applicable to ac circuit?

Physics
1 answer:
Sedaia [141]2 years ago
8 0
Yes, they both are, and you'd just be working with complex numbers instead of real number.
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A filing cabinet weighing 556 N rests on the floor. The coefficient of static friction between it and the floor is 0.68, and the
zvonat [6]

Explanation:

"Static friction is a force that keeps an object at rest. It must be overcome to start moving the object."

(556 x 0.68) = static friction of 378.08N. before movement occurs.

The  forces (a) and (b) will not move it.  

Each will incur a frictional force preventing movement equal to itself, = 222N. and 334N. respectively.

Forces (c) and (d) will move it, and accelerate it.

Forces (c) and (d) will both encounter friction of (556 x 0.56) = 311.36N. when the cabinet is moving.

5 0
3 years ago
How is displacement different from distance?
Anni [7]

Answer:

i do belive its C

Explanation:

i remeber this question from somewhere also it makes the most sense

5 0
3 years ago
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What is true of the moon's orbital and rotational periods?
Eddi Din [679]
The moon's orbital and rotational periods are identical or the same, I<span>ts rate of spin is done in unison with its rate of revolution (the time that is needed to complete one orbit). Thus, the moon rotates exactly once every time it circles the Earth.</span>
4 0
3 years ago
Which would have the longer orbital period: a moon 1 million km from the center of Jupiter, or a moon 1 million km from the cent
Harman [31]

Answer:

earth

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The formula for the orbital period of the moon is given by

T = 2\pi \sqrt{\frac{r}{g}}

As the time period is inversely proportional to the square root of the acceleration due to gravity of the planet.

As the value of acceleration due to gravity on Jupiter is more than the earth, so the period of moon around the earth is large as compared to the period of the moon around the Jupiter when the distance is same.

5 0
3 years ago
What is the kinetic energy of a 9.0 kg steelhead if its speed is 16 m/s?
Vesnalui [34]

<u>We are given:</u>

Mass of the Steelhead(m) = 9 kg

Velocity of the Steelhead(v) = 16 m/s

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KE = 1/2mv²

replacing the variables

KE = 1/2 * 9 * (16)²

KE = 1152 Joules

8 0
2 years ago
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