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IrinaK [193]
3 years ago
11

Is a compound considered a pure substance?

Physics
1 answer:
IgorLugansk [536]3 years ago
7 0

Answer:

It depends on which compound you use carbon dioxide can be while helium will not but if you where to sum it up it would be use because simply most compounds are considered pure substance.

Explanation:

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Init. A
Gekata [30.6K]

Answer:

v = 1/3 m / s = 0.333 m / s

in the direction of the truck

Explanation:

The average speed is defined by the variation of the position between the time spent

           v = Δx / Δt

since the position is a vector we must add using vectors, we will assume that the displacement to the right is positive, the total displacement is

           Δx = 20 - 15 +20

           Δx = 25 m

therefore we calculate

         v = 25/75

         v = 1/3 m / s = 0.333 m / s

in the direction of the truck

7 0
3 years ago
Eyeglasses bend light help the image form properly on the retina. The bending of light as it passes from one medium to another i
garri49 [273]
It's refraction....When light bends on passing from one medium to another is refraction !
3 0
4 years ago
Read 2 more answers
How does increasing the tension of a spring affect a wave on the spring?
umka21 [38]

When waves travel across strings, the larger the tension of the string the faster the velocity of the wave. This is because of the equation:

v = the square root of (T/(m/L)) where T is the tension, m the mass of the string, and L the length of the string

Hope this helps!


5 0
3 years ago
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If a current of 2.4 a is flowing in a cylindrical wire of diameter 2.0 mm, what is the average current density in this wire?
Gnom [1K]

The average current density in the wire is given by:

J=\frac{I}{A}

where I is the current intensity and A is the cross-sectional area of the wire.


The cross-sectional area of the wire is given by:

A=\pi r^2

where r is the radius of the wire. In this problem, r=\frac{d}{2}=\frac{2.0 mm}{2}=1.0 mm=0.001 m, so the cross-sectional area is

A=\pi (0.001 m)^2=3.14 \cdot 10^{-6} m^2


and the average current density is

J=\frac{I}{A}=\frac{2.4 A}{3.14 \cdot 10^{-6} m^2}=7.64 \cdot 10^5 A/m^2

8 0
3 years ago
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Which components are part of all types of scientific investigations
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• 1st Making an observation                                                                                       •2nd Starting a question                                                                                           •3rd Formulating a hypothesis                                                                                     • 4th Conducting an experiment, then...                                                                       • Finally, Analyzing the data & writing down/drawing conclusions
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3 years ago
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