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KonstantinChe [14]
2 years ago
5

What is the specific heat of a substance that absorbs 2500 joules of heat when a sample of 100g of the substance increases in te

mperature from 10.°C to 70.°
Chemistry
1 answer:
Ierofanga [76]2 years ago
5 0

Answer:

0.417 J/gºC

Explanation:

From the question given above, the following data were obtained:

Heat (Q) absorbed = 2500 J

Mass (M) of substance = 100 g

Initial temperature (T1) = 10 °C

Final temperature (T2) = 70 °C

Specific heat capacity (C) =?

Next, we shall determine the change in temperature (ΔT). This can be obtained as follow:

Initial temperature (T1) = 10 °C

Final temperature (T2) = 70 °C

Change in temperature (ΔT) =?

Change in temperature (ΔT) = T2 – T1

Change in temperature (ΔT) = 70 – 10

Change in temperature (ΔT) = 60 °C

Finally, we shall determine the specific heat capacity of the substance as follow:

Heat (Q) absorbed = 2500 J

Mass (M) of substance = 100 g

Change in temperature (ΔT) = 60 °C

Specific heat capacity (C) =?

Q = MCΔT

2500 = 100 × C × 60

2500 = 6000 × C

Divide both side by 6000

C = 2500 / 6000

C = 0.417 J/gºC

Therefore, the specific heat capacity of substance is 0.417 J/gºC

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Answer:

What happens when it is squeezed is that its volume increases, the pressure of the material increases.

Explanation:

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What element is reduced in the following reaction?
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A certain gas is present in a 15.0 LL cylinder at 2.0 atmatm pressure. If the pressure is increased to 4.0 atmatm the volume of
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Explanation:

According to Boyle's law,  pressure of a gas is inversely proportional to its volume at constant temperature and moles.

Mathematically,       P = \frac{k}{V}

where,     k = proportionality constant

Also, formula for initial pressure and volume is as follows.

              P_{i} = \frac{k_{i}}{V_{i}}

or,           k_{i} = P_{i} \times V_{i}

                          = 2 atm \times 15 L

                          = 30 atm L

Now, we will calculate the value of k_{f} as follows.

             k_{f} = P_{f} \times V_{f}

                         = 4 atm \times 7.5 L

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What is formed when atoms of elements combine?
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A rubber ball is held 4.0 m above a concave spherical mirror with a radius of curvature of 1.5 m. At time equals zero, the ball
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The time elapsed when the ball placed above the concave mirror and the image formed would be at the same location is 0.55 s.

<h3>Image distance</h3>

The position of the image formed is determined using the followimg mirror formula;

\frac{1}{f} = \frac{1}{v} + \frac{1}{u}

where;

  • f is the focal length of the mirror
  • v is the image distance
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f = R/2

f = 1.5/2

f = 0.75 m

When the ball and its image is in the same position, u = v

The position of the ball is calculated as;

\frac{1}{f} = \frac{1}{u} + \frac{1}{u} \\\\\frac{1}{f} = \frac{2}{u} \\\\u = 2f\\\\u = 2(0.75)\\\\u = 1.5 \ m

<h3>Time of motion of the ball</h3>

The time taken for the ball to travel the caluclated distance is determined as;

h = ut + ¹/₂gt²

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1.5 = 4.9t²

t² = 1.5/4.9

t² = 0.306

t = 0.55 s

Thus, the time elapsed when the ball and its image are at the same location is 0.55 s.

Learn more about concave mirror here: brainly.com/question/7512320

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