Answer:
2.7 × 10⁻⁴ bar
Explanation:
Let's consider the following reaction at equilibrium.
SbCl₅(g) ⇄ SbCl₃(g) + Cl₂(g)
The pressure equilibrium constant (Kp) is 3.5 × 10⁻⁴. We can use these data and the partial pressures at equilibrium of SbCl₅ and SbCl₃, to find the partial pressure at equilibrium of Cl₂.
Kp = pSbCl₃ × pCl₂ / pSbCl₅
pCl₂ = Kp × pSbCl₅ / pSbCl₃
pCl₂ = 3.5 × 10⁻⁴ × 0.17 / 0.22
pCl₂ = 2.7 × 10⁻⁴ bar
213034 torr is the osmotic pressure.
Explanation:
osmotic pressure is calculated by the formula:
osmotic pressure= iCrT
where i= no. of solute
c= concentration in mol/litre
R= Universal Gas constant
T = temp
It is given that solution is 3% which is 3gms in 100 ml.
let us calculate the concentration in moles/litre
3gm/100ml*1000ml/1L*1mol NaCl/55.84g NaCl
= 5.372 gm/litre
Putting the values in the formula, Temp in Kelvin 318.5K
osmotic pressure= 2*5.372*0.083 * 318.5 Gas constant 0.083
= 284.023 bar or 213018 torr. c= 5.372 moles/L
i=2 for NaCl
3. I am not sure what is meant by shape, it could be to do with structure.
4. It is magnesium nitride, as adding nitrogen makes a nitride
First, we have to start balancing the equation:
H2O2 + FeSO4 + H2SO4 → Fe2(SO4)3 + H2O
we can see that the number of H atoms on the left side is 4 and on the right side is 2 so we have to make the number of H atoms are equal on both sides
so, we will put 2H2O instead of H2O
H2O2 + FeSO4 + H2SO4 → Fe2(SO4)3 + 2H2O
we can see that number of O on the left side is 10 and on the right side 14
so we will put 2 FeSO4 instead of FeSO4
H2O2 + 2FeSO4 + H2SO4 → →Fe2(SO4)3 + 2H2O
∴ the coefficients of the reactants and products will be in order 1 2 1 1 2
