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Vera_Pavlovna [14]
3 years ago
5

200 g of solid sodium hydroxide (NaOH) are dissolved in 750 mL of water. What is the concentration of this solution?

Chemistry
1 answer:
Anastaziya [24]3 years ago
8 0

Answer:

6.67 M

Explanation:

Molarity = \frac{mol}{L}

<em>Convert 200g NaOH to moles. Convert 750 mL to L.</em>

200 g NaOH x (1 mol/39.998 g) = 5.00025... mol NaOH

750 mL x (1 L/1000 mL) = 0.750 L

<em>Substitute values into the equation.</em>

Molarity = \frac{5.00025}{0.750}

Molarity = 6.667... M

Molarity = 6.67 M

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Answer:

V₂ = 5.97 L

Explanation:

Given data:

Initial temperature = 9°C (9+273 = 282 K)

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Solution:

Formula:

The Charles Law will be apply to solve the given problem.

According to this law, 'the volume of given amount of a gas is directly proportional to its temperature at constant number of moles and pressure'

Mathematical expression:

V₁/T₁ = V₂/T₂

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T₁ = Initial temperature

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T₂ = Final temperature

Now we will put the values in formula.

V₁/T₁ = V₂/T₂

V₂ = V₁T₂/T₁  

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Given the following reaction: 2D(g) + 3E(g) + F(g) \longrightarrow⟶ 2G(g) + H(g) When the concentration of D is decreasing by 0.
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Answer:

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Explanation:

Rate of reaction = -d[D] / 2dt  = -d[E]/ 3dt = -d[F]/dt  = d[G]/2dt = d[H]/dt

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