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salantis [7]
3 years ago
6

The shortest side in the triangle in Exercise 3 is opposite the angle(s). (number only)

Mathematics
2 answers:
Sati [7]3 years ago
6 0

Answer:

62°

Step-by-step explanation:

180-56= 124

124/2=62°

Lelechka [254]3 years ago
6 0
I agree with them^^ 62
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When you purchase an item with a credit card, you might not ever have to pay for it. True False
Sergio039 [100]
False. You get billed by the end of the month the money is “borrowed” money from the bank until you have to pay it all back, if it’s not paid on time you have to pay extra (interest). With debit card your money is taken out immediately.
6 0
3 years ago
Find a quadratic function that includes the set of values below.<br> (0,9). (2,15) (3,12)
nlexa [21]

Answer:

f(x) = -2x^2 + 7x + 9

Step-by-step explanation:

f(x) = ax^2 + bx + c\\f(0) = 9 => c = 9;\\f(2) = 15 = 4a + 2b + 9  2a + b  = 3\\f(3) = 9a + 3b + 9 = 12  3a + b = 1\\Subtract the second equation from the first:\\-a = 2 => a = -2; b = 7; c = 9\\f(x) = -2x^2 + 7x + 9

3 0
4 years ago
What is the slope in the equation:<br> y= 3/4x - 1
Basile [38]

Answer: the slope is 3/4.

y=mx+b and m is always the slope.

3 0
3 years ago
Read 2 more answers
Someone please help me asap!
miskamm [114]

I think the correct answer is C. because each if forming a right triangle when you trace it.

If i'm correct brainliest please

3 0
3 years ago
Please help asap find f -1
ExtremeBDS [4]
I.
Given a function f with domain D and range R, and the inverse function 
f ^{-1},

then the domain of f ^{-1} is the range of f, and the range of f ^{-1} is the domain of f.

II. We are given the function f(x)= \sqrt{x-5},

the domain of f, is the set of all x for which \sqrt{x-5} makes sense, so x is any x for which x-5\geq0, that is x≥5.

the range is the set of all values that f can take. Since f is a radical function, it never produces negative values, in fact in can produce any value ≥0

Thus the Domain of f is [5, ∞) and the Range is [0, ∞)
then , the Domain of f ^{-1} is [0, ∞) and the Range of f ^{-1} is [5, ∞) 

III.
Consider f(x)= \sqrt{x-5}

to find the inverse function f^{-1}, 

1. write f(x) as y:

y= \sqrt{x-5}

2. write x in terms of y:

y= \sqrt{x-5}

take the square of both sides

y^{2} =x-5

add 5 to both sides

y^{2} +5=x

x=y^{2} +5

3. substitute y with x, and x with f^{-1}(x):

f^{-1}(x)=x^{2} +5


These steps can be applied any time we want to find the inverse function.

IV. Answer: 

f^{-1}(x)=x^{2} +5, x≥0

y≥0, where y are all the values that f^{-1} can take

Remark: the closest choice is B

8 0
3 years ago
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