The three main parts of an atom are protons, neutrons<span>, and </span>electrons<span>. </span>Protons<span> - have a positive charge, located in the </span>nucleus<span>, </span>Protons<span> and </span>neutrons<span> have nearly the same mass while </span>electrons<span> are much less massive. </span>Neutrons<span>- Have a negative charge, located in the </span><span>nucleus</span>
Answer:
4. All of the above
Explanation:
The purpose of striking the ball in a volleyball game:
From the serve you could state that you need to place the ball in motion.
When returning a shot of, you normally want to change the direction of the ball's motion.
During a dropshot, you purposely want to slow down the ball's motion.
The correct answer must be all of the above.
Here are the observations
<u>S</u><u>u</u><u>g</u><u>a</u><u>r</u><u>:</u><u>-</u>
- Sugar is soluble in water
- so It will dissolve in water .
<u>C</u><u>o</u><u>r</u><u>n</u><u> </u><u>s</u><u>y</u><u>r</u><u>u</u><u>p</u><u>:</u><u>-</u>
- Corn syrup is also basically a sugar.
- It will dissolve in water too .
- If we shake the mixture in glass then corn syrup will be dissolved.
<u>O</u><u>i</u><u>l</u><u>:</u><u>-</u>
- Oil is not soluble in water
- Hence it won't dissolve in water.
- It will float over water and make two layers
Answer:
a)
b)
Explanation:
Given:
mass of bullet, 
compression of the spring, 
force required for the given compression, 
(a)
We know

where:
a= acceleration


we have:
initial velocity,
Using the eq. of motion:

where:
v= final velocity after the separation of spring with the bullet.


(b)
Now, in vertical direction we take the above velocity as the initial velocity "u"
so,

∵At maximum height the final velocity will be zero

Using the equation of motion:

where:
h= height
g= acceleration due to gravity


is the height from the release position of the spring.
So, the height from the latched position be:



<span>The correct answer should be B) 63.55. That's because the most precise number is 63.546, but you would write 55 because 46 is rounded that way in the equation. The others are a bit higher, while E is a completely different element, Iodine. This isn't the most precise piece of data because in reality there would be a slight differentiation of +- 0,003u</span>