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agasfer [191]
3 years ago
8

Which of the following describes the effect of a convex mirror on light rays?

Physics
1 answer:
natulia [17]3 years ago
3 0
B. It reflects light rays outward.

A convex mirror looks like this ⊂.  So when light rays hit the outward curves, it bends the light rays outwards, and backwards,  and it would appear to be coming from its center called the focus.

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A tugboat pulls a ship with a constant net horizontal force of 4.71 × 103 N and causes the ship to move through a harbor. How mu
Studentka2010 [4]

Answer:

21.53 x 10^{6} N

Explanation:

force (F) = 4.71 x 10^{3} N

distance (s) = 4.57 km = 4570 m

how much work is done.

work = force x distance

work = 4.71 x 10^{3} x 4570 = 21.53 x 10^{6} N

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When Momentum is conserved it is called ________ .​
mestny [16]

Answer:

When Momentum is conserved it is called conservation of momentum

Explanation:

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Sunlight is a form of electromagnetic energy.
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Answer: True

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3V battery is used with a 15 ohm resistance.What is the current?
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Answer:

0.2 A

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V= IR

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5 0
2 years ago
Recall from Chapter 1 that a watt is a unit of en- ergy per unit time, and one watt (W) is equal to one joule per second ( J·s–1
harkovskaia [24]

Answer:

Explanation:

The energy of a photon is given by the equation E_p=h f, where h is the <em>Planck constant</em> and f the frequency of the photon. Thus, N photons of frequency f will give an energy of E_N=N h f.

We also know that frequency and wavelength are related by f=\frac{c}{\lambda}, so we have E_N=\frac{N h c}{\lambda}, where c is the <em>speed of light</em>.

We will want the number of photons, so we can write

N=\frac{\lambda E_N}{h c}

We need to know then how much energy do we have to calculate N. The equation of power is P=E/t, so for the power we have and considering 1 second we can calculate the total energy, and then only consider the 4% of it which will produce light, or better said, the N photons, which means it will be E_N.

Putting this paragraph in equations:

E_N=(\frac{4}{100})E=0.04Pt=(0.04)(100W)(1s)=4J.

And then we can substitute everything in our equation for number of photons, in S.I. and getting the values of constants from tables:

N=\frac{\lambda E_N}{h c}=\frac{(520 \times10^{-9}m) (4J)}{(6.626\times10^{-34}Js) (299792458m/s)}=1.047 \times10^{19}

3 0
3 years ago
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