Question 2 (10 points)
2 answers:
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Answer:
(a) 2.45×10⁵ N/m
(b) 0.204 m
Explanation:
Here we have that to have a velocity of 2.25 m/s then the relationship between the elastic potential energy of the spring and the kinetic energy of the rocket must be
Elastic potential energy of the spring = Kinetic energy of the rocket
Where:
k = Force constant of the spring
x = Extension of the spring
m = Mass of the rocket
v = Velocity of the rocket
Therefore,
or
(b) Since the maximum acceleration is given as 5.00×g we have
Maximum acceleration = 5.00 × 9.81 = 49.05 m/s²
Hence the force on the rocket is then;
Force = m×a = 1020 × 49.05 = 50,031 N
Therefore,
(a) From which
or
Force constant of the spring, k = 2.45×10⁵ N/m.