All categories

3 years ago

Why isn't pluto considered a planet anymore?

Physics

1 answer:

aivan3 [116]3 years ago

3 0

The answer is. It did not meet the three criteria the IAU uses to define a full-sized planet.

1. It is in orbit around the Sun

2. It has sufficient mass to assume hydrostatic equilibrium

3. It has 'cleared the neighborhood' around its orbit

Pluto has not 'cleared its neighborhood'

You might be interested in

If a scale on Earth reads 650 N, what is your mass?

OlgaM077 [116]

If the scale reads 650N, then the mass of whoever it is standing on the scale is

(weight) / (gravity) = (650N) / (9.8 m/s²) = 66.3 kilograms .

It's not MY mass, even if I'm the one standing on the scale.
If I stand on a scale and it reads 650 N, the scale is broken.

4 0

3 years ago

A metal wire has a resistance of 13.00 at a temperature of 25.0 degree celsius

Nady [450]

Explanation:

what exactly are you asking for?

4 0

3 years ago

How do you think overpumping groudwater is related to the formation of sinkholes?

vladimir2022 [97]

Ground water keept the ground at a stable level when it is gone the cavern it was in has no support and is at risk of callaps

3 0

4 years ago

A large magnetic flux change through a coil must induce a greater emf in the coil than a small flux change. A) True B) False

bixtya [17]

Answer:

False

Explanation:

Faraday's law gives the relationship between the induced emf and the rate of change of magnetic flux i.e.

$\epsilon=\dfrac{-d\phi}{dt}$

The given statement "A large magnetic flux change through a coil must induce a greater emf in the coil than a small flux change" is false. The reason is that if the rate of change of magnetic flux is greater, then its will induce more emf. It would mean it does not say about emf.

Hence, it is false.

3 0

4 years ago

A car is moving at 19 m/s along a curve on a horizontal plane with radius of curvature 49m.

JulsSmile [24]

Answer:

$\mu =0.75$

Explanation:

<u>Frictional Force </u>

When the car is moving along the curve, it receives a force that tries to take it from the road. It's called centripetal force and the formula to compute it is:

$F_c=m.a_c$

The centripetal acceleration a_c is computed as

$\displaystyle a_c=\frac{v^2}{r}$

Where v is the tangent speed of the car and r is the radius of curvature. Replacing the formula into the first one

$F_c=m.\frac{v^2}{r}$

For the car to keep on the track, the friction must have the exact same value of the centripetal force and balance the forces. The friction force is computed as

$F_r=\mu N$